In: Biology
Question 1
The correct answer is option a - AUGAUGILECCUUAG
Explanation: First methionine called fmet is removed from most of the proteins. So, to retain methinine in the tripeptide, there should be two methionine at the begining. One will be removed, and the other will be retained. at the last there should be one stop codon , so that protein synthesis stop at that position. So UAG is a stop codon present at the last .
Question 2 - The correct answer is option d-16.
Explanation: There are total 16 codons which begin with U, among them 3 codes for stop codons (UAG, UAA and UGA) and rest 13 codes for different amino acids. ]
UUU and UUC -Phe,
UUA and UUG -leu ,
UCA, UCG,UCU UCC - ser
UGU and UGC- Cys
UGG-trp
UAU and UAC -tyr
Question 3
The correct answer is option c -UAG
Explanation: Codon sequence is AUC, so its complementary sequence is UAG, so anticodon is UAG.
Question 4
The correct answer is option d -the TYC, aminoacyl, anticodon and D arms
Explanation: tRNA is clover leaf like structure which is formed by different stem and lop structure. Four arms are anticodon stem and loop, TYC stem and loop, D arms and loop and aminoacyl stem. All of these structures together form the clover leaf structure of tRNA.
Question 5
The correct answer is option d - the mRNA of bacteria goes directly to the ribosome from the polymerase
Explanation: In bacteria transcription and translation occur simultaneously. So mRNA started translation where it is being transcribed by RNA Polymerase. In eukaryotes transcription occur in the nucleus and after transport of mRNA into the cytoplasm from nucleus, it is translated. But in prokaryotes, both f the process occur simultaneously in the cytoplasm. So rate of translation is much high in bacteria in comparison to eukaryotes.
If these answers help you, please give a thumb up reaction. Thank you.