In: Statistics and Probability
With increases in obesity rates over the past several decades, health care providers have become concerned about the effects of obesity on health. As a health psychologist, you are interested in people’s perceptions and responses to food as this might influence obesity. You are curious if people that are impulsive or have difficult with impulse control are more likely to be obese and if they perceive sweet, high calorie foods as being more desirable than the general population. Given this, you screen a group of participants and recruit participants (n=20) that have high impulsivity scores (that is, they are more impulsive). From your sample, you collect participant’s weight and scores on the Food Perception Inventory (FPI) which measures individual’s preference for high calorie foods. For obesity, you know the national mean (168) and standard deviation (26.38), but you only know the population mean (103) for the FPI. Using the data below, answer the following questions:
Participant ID |
Weight |
FPI |
1 |
204 |
115 |
2 |
198 |
111 |
3 |
219 |
119 |
4 |
250 |
122 |
5 |
170 |
105 |
6 |
232 |
110 |
7 |
178 |
104 |
8 |
177 |
107 |
9 |
192 |
109 |
10 |
198 |
110 |
11 |
203 |
115 |
12 |
211 |
114 |
13 |
198 |
112 |
14 |
212 |
120 |
15 |
215 |
119 |
16 |
236 |
120 |
17 |
196 |
115 |
18 |
198 |
115 |
19 |
180 |
112 |
20 |
210 |
121 |
Questions:
1. Calculate a one sample test for Weight and report the result
2. What is your decision for Weight (how will you determine if this sample is unique or rare)? Interpret your result
3. Calculate a one sample test for FPI and report the result
4. What is your decision for FPI? Interpret your result
1. The results are:
168.000 | hypothesized value |
203.850 | mean Weight |
20.402 | std. dev. |
4.562 | std. error |
20 | n |
19 | df |
7.858 | t |
2.18E-07 | p-value (two-tailed) |
2. The p-value is 0.0000.
Since the p-value (0.0000) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that µ ≠ 168.
3. The results are:
103.000 | hypothesized value |
113.750 | mean FPI |
5.340 | std. dev. |
1.194 | std. error |
20 | n |
19 | df |
9.003 | t |
2.78E-08 | p-value (two-tailed) |
4. The p-value is 0.0000.
Since the p-value (0.0000) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that µ ≠ 103.