Question

In: Statistics and Probability

studying enough in a four credit hour math class-supposed to be 480 minutes -list of times...

studying enough in a four credit hour math class-supposed to be 480 minutes

-list of times in minutes (504, 267, 220, 322, 538, 542, 428, 481, 413, 302, 602)

Find:

-observed value

-predicted z-score for each observed value

-correlation coefficient from linear regression

-is this sample approximately normal? why?

-sample mean

-sample deviation

Solutions

Expert Solution

For the given data, we may enter the observed values and the corresponding Z scores in the form a table:

where, Z score is nothing but the standardized value of observations, by dividing the difference between the observed value and the sample mean by the standard deviation:

Computing the sample mean:

= 419.909

Computing the sample standard deviation:

= 126.396

Hence, the Z score can be obtained using the equation:

Substituting the observed values:

Observed Value (X) Z Score (Z)
504 Z = (504 - 419.909) / 126.396 = 0.67
267 Z = (267 - 419.909) / 126.396 = -1.21
220 Z = (220 - 419.909) / 126.396 = -1.58
322 Z = (322 - 419.909) / 126.396 = -0.77
538 Z = (538 - 419.909) / 126.396 = 0.93
542 Z = (542 - 419.909) / 126.396 = 0.97
428 Z = (428- 419.909) / 126.396 = 0.06
481 Z = (481- 419.909) / 126.396 = 0.48
413 Z = (413 - 419.909) / 126.396 = -0.05
302 Z = (302- 419.909) / 126.396 = -0.93
602 Z = (602- 419.909) / 126.396 = 1.44

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