In: Chemistry
1.5×10−2 M Sr(NO3)2
Express your answer using two significant figures.
Part B
1.5×10−2 M NaF
Express your answer using two significant figures.
1.5×10−2 M Sr(NO3)2
SrF2 --------------> Sr^2+ (aq) + 2F^-
s 2s
s+ 1.5*10^-2 2s
Ksp = [Sr^2+][F^-]^2
4.3*10^-9 = s+1.5*10^-2*(2s)^2
4.3*10^-9 = s+1.5*10^-2*(2s)^2 [ s+1.5*10^-2 = 1.5*10^-2]
4.3*10^-9 = 1.5*10^-2*(2s)^2
4s^2 = 4.3*10^-9/1.5*10^-2
4s^2 = 2.86*10^-7
s^2 = 7.15*10^-8
s = 2.67*10^-4M
solubility of SrF2 = 2.67*10^-4M
Part B
1.5×10−2 M NaF
SrF2 --------------> Sr^2+ (aq) + 2F^-
s 2s
s 2s+1.5*10^-2
Ksp = [Sr^2+][F^-]^2
2.5*10^-9 = s*(2s+1.5*10^-2)^2 [ 2s+1.5*10^-2 = 1.5*10^-2 ]
4.3*10^-9 = s*(1.5*10^-2)^2
s = 4.3*10^-9/(1.5*10^-2)^2
s = 1.9*10^-5 M
solubility of SrF2 is 1.11*10^-5 M