Question

In: Statistics and Probability

1.) Use the definitions given in the text to find both the odds for and the...

1.) Use the definitions given in the text to find both the odds for and the odds against the following event.

-Flipping 4 fair coins and getting 0 heads.

The odds for getting 0 heads are what to what.​(Type a whole​ number.)

The odds against getting 0 heads are what to what. (Type a whole number)

2.) Determine whether the following individual events are overlapping or​ non-overlapping. Then find the probability of the combined event.

Getting a sum of either 4 or 8 on a roll of two dice

Choose the correct answer below​ and, if​ necessary, fill in the answer box to complete your choice.

3.)Determine the probability of having 2 girls and 3 boys in a 5​-child family assuming boys and girls are equally likely.  

The probability of having 2 girls and boy sis is?

4.) Use the​ "at least​ once" rule to find the probabilities of the following event.

Getting at least one head when tossing seven fair coins

Solutions

Expert Solution

1) no. of events corresponding to flipping 4 coins= =16

no. of events where heads don't appear=1

no. of events where heads don't appear=15

therefore odds of getting 0 heads =1/15

odds against getting 0 heads=15/1

2)events where the sum is 4={(1,3),(2,2),(3,1)}

events where the sum is 8={(2,6),(3,5),(4,4),(5,3),(6,2)}

the events are not overlapping as no common element is there in both the events

no. of events where sum is 4=3

no. of events where sum is 8=5

total no. events=6*6=36

therefore the probability of getting a sum kof 4 or 9=(3+5)/36=2/9

3)since the boys and girls are equally likely events

probability of each event=1/2

therefore probability of 2 girls and 3 boys is== 10/32=0.3125

here is the no. of ways 2 girls and 3 boys can be arranged in terms of the time they are born and 1/2 the probability of each of the 5 events of a boy or girl being born

4)no. of events of flipping 7 coins and getting no head=1

total no. of events of flipping 7 coins==128

probability of getting no head=1/128

probability of getting atleast one head=1-P(no head) = 1-(1/128) = 127/128


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