In: Statistics and Probability
Given the following sample information, test the hypothesis that the treatment means are equal at the 0.10 significance level:
Treatment 1 | Treatment 2 | Treatment 3 |
3 | 9 | 6 |
2 | 6 | 3 |
5 | 5 | 5 |
1 | 6 | 5 |
3 | 8 | 5 |
1 | 5 | 4 |
4 | 1 | |
7 | 5 | |
6 | ||
4 | ||
a. State the null hypothesis and the alternative hypothesis.
H0 : μ1 (Click to select) = > < μ2 (Click to select) = > < μ3
H1 : Treatment means (Click to select) are not are all the same.
b. What is the decision rule? (Round the final answer to 2 decimal places.)
Reject H0 if F > .
c. Compute SST, SSE, and SS total. (Round the final answers to 2 decimal places.)
SST =
SSE =
SS total =
d. Complete the ANOVA table. (Round the
SS, MS, and F values to 2 decimal places.)
Source | SS | DF | MS | F | ||
Factor | ||||||
Error | ||||||
Total | ||||||
e. State your decision regarding the null hypothesis.
Decision: (Click to select) Reject Do not reject H0.
f.Find the 95% confidence interval for the difference between treatment 2 and 3. (Round the final answers to 2 decimal places.)
95% confidence interval is: ±
We can conclude that the treatments 2 and 3 are (Click to select) different the same .