25.00 mL of 0.185 M HCN (Ka = 4.90 x 10^-10) was titrated with 18.50 mL...

25.00 mL of 0.185 M HCN (Ka = 4.90 x 10^-10) was titrated with 18.50 mL of Ca(OH)2. What is the pH of the original HCN solutuon? What is the pH after 9.25 mL of base have been added?

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Expert Solution

A. The pH of the original HCN solution is 5.20 (approx)

B. The pH of the solution after addition of 9.25 mL of base is 9.01 (approx)

queen_honey_blossom answered 1 year ago

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