25.00 mL of 0.185 M HCN (Ka = 4.90 x 10^-10) was titrated with 18.50 mL...

25.00 mL of 0.185 M HCN (Ka = 4.90 x 10^-10) was titrated with 18.50 mL of Ca(OH)2. What is the pH of the original HCN solutuon? What is the pH after 9.25 mL of base have been added?

Expert Solution

A. The pH of the original HCN solution is 5.20 (approx)

B. The pH of the solution after addition of 9.25 mL of base is 9.01 (approx)

queen_honey_blossom answered 2 years ago

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