The reaction of CH3OH(g) with N2(g) to give HCN(g), NH3(g), and O2(g) requires 164 kJ/mol of...

The reaction of CH3OH(g) with N2(g) to give HCN(g), NH3(g), and O2(g) requires 164 kJ/mol of CH3OH(g).

a) Write a balanced chemical equation for this reaction. Include the phases of all species in the reaction.

b)Should the thermal energy involved be written as a reactant or as a product?

c) How much heat is involved in the reaction of 70.0 g of CH3OH(g) with excess N2(g) to give HCN(g) and NH3(g) in this reaction?

Solutions

Expert Solution

(a) Balanced chemical equation is:

2 CH₃OH_(g) + 2N2(g) + 164kj 2HCN_(g₎ + 2NH₃ +O_2(g)

(b) The thermal energy here is energy absorbed for every mole of methanol hence it should be written with reactants.

1mol of methanol= 32g =164kj of heat

1g of methanol will absorb 164/32 kj of heat

70 g of methanol will absorb= 164/32*70 kj of heat

= 358.75kj

queen_honey_blossom answered 1 year ago

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