In: Chemistry
how many molecules of carbon tetrachloride are there
in 80g of ccl4 sample
no of molecules = no of moles * 6.023*10^23
gram molar mass of CCl4 = 154g/mole
weight of CCl4 = 80g
no of molecules = no of moles * 6.023*10^23
= ( W/G.M.Wt ) * 6.023*10^23
= 80*6.023*10^23/154 = 3.13*10^23 molecules>>>>>>answer