In: Statistics and Probability
Solution :
Given, X follows Normal distribution with,
= 31
2
= 25 ,
= 5
A sample of size n = 18 is taken from this population.
Let
be the mean of sample.
The sampling distribution of the
is approximately normal with
Mean
=
= 31
SD
=
= 5/
18
= 1.17851130198
Find P(X > 29)
= P[(X -
)/
> (29 -
)/
]
= P[Z > (29 - 31)/1.17851130198]
= P[Z > -1.70]
= 1 - P[Z < -1.70]
= 1 - 0.0446 ......... ( use z table)
= 0.9552 = 0.96