Question

In: Statistics and Probability

Twelve batteries were tested to see how many hours they would last. The frequency is Hours...

Twelve batteries were tested to see how many hours they would last. The frequency is
Hours Frequency (f) Midpoint (Xm) f*Xm C f (X - X̅ )² f (X - X̅ )²
1-3 1 1+3/2 = 4/2 = 2 1x2 = 2 1 27.5625 27.5625
4-6 4 4+6/2= 10/2= 5 4x5 = 20 1+4 = 5 5.0625 20.25
7-9 5 7+9/2 = 16/2 = 8 5x8 = 40 1+4+5 = 10 0.5625 2.8125
10-12 1 10+12 = 22/2 = 11 1x11 = 11 (1+4+5+1) = 11 14.0625 14.0625
13-15 1 13+15 = 28/2 = 14 1x14 = 14 (1+4+5+1+1)= 12 45.5625 45.5625
Total 12 87 92.8125 110.25

Median

Range:

3rd Quartile:

45th Percentile:

Solutions

Expert Solution

MEdian:

Range:

Highest number = 15 in the hours: Lowest number - 1

Range = 15 - 1 = 14

3rd Quartile:

45th Percentile:

:


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