Question
In: Statistics and Probability
Twelve batteries were tested to see how many hours they would last. The frequency is Hours...
| Twelve batteries were tested to see how many hours they would last. The frequency is | ||||||
| Hours | Frequency (f) | Midpoint (Xm) | f*Xm | C f | (X - X̅ )² | f (X - X̅ )² |
| 1-3 | 1 | 1+3/2 = 4/2 = 2 | 1x2 = 2 | 1 | 27.5625 | 27.5625 |
| 4-6 | 4 | 4+6/2= 10/2= 5 | 4x5 = 20 | 1+4 = 5 | 5.0625 | 20.25 |
| 7-9 | 5 | 7+9/2 = 16/2 = 8 | 5x8 = 40 | 1+4+5 = 10 | 0.5625 | 2.8125 |
| 10-12 | 1 | 10+12 = 22/2 = 11 | 1x11 = 11 | (1+4+5+1) = 11 | 14.0625 | 14.0625 |
| 13-15 | 1 | 13+15 = 28/2 = 14 | 1x14 = 14 | (1+4+5+1+1)= 12 | 45.5625 | 45.5625 |
| Total | 12 | 87 | 92.8125 | 110.25 | ||
Median
Range:
3rd Quartile:
| 45th Percentile: |
Solutions
Expert Solution
MEdian:
Range:
Highest number = 15 in the hours: Lowest number - 1
Range = 15 - 1 = 14
3rd Quartile:
|
45th Percentile: |
:
orchestra answered 1 year agoRelated Solutions
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