In: Statistics and Probability
A sample of 50 employees of Tucson Inc. were asked the following question and their response was carefully recorded.
Taken everything together, how satisfied are you with your job at Tucson Inc.?
A Completely Satisfied
B Satisfied
C Neither satisfied nor dissatisfied
D Dissatisfied
E Completely Dissatisfied
B |
C |
C |
A |
D |
D |
E |
E |
C |
C |
C |
D |
C |
C |
C |
C |
C |
C |
C |
C |
B |
C |
B |
B |
B |
B |
A |
A |
A |
C |
E |
C |
B |
B |
D |
C |
E |
C |
D |
A |
A |
A |
E |
E |
C |
C |
C |
B |
B |
B |
Reconsider, and assume that A = 5, B = 4, C = 3, D = 2, and E = 1.
What is the Mean job satisfaction? Are the employees on average satisfied?
What is the Median job satisfaction?
What is the Mode of job satisfaction?
Calculate 25th, 50th, and 75th percentiles.
putting above data in ascending order:
S. no | X |
1 | 1 |
2 | 1 |
3 | 1 |
4 | 1 |
5 | 1 |
6 | 1 |
7 | 2 |
8 | 2 |
9 | 2 |
10 | 2 |
11 | 2 |
12 | 3 |
13 | 3 |
14 | 3 |
15 | 3 |
16 | 3 |
17 | 3 |
18 | 3 |
19 | 3 |
20 | 3 |
21 | 3 |
22 | 3 |
23 | 3 |
24 | 3 |
25 | 3 |
26 | 3 |
27 | 3 |
28 | 3 |
29 | 3 |
30 | 3 |
31 | 3 |
32 | 3 |
33 | 4 |
34 | 4 |
35 | 4 |
36 | 4 |
37 | 4 |
38 | 4 |
39 | 4 |
40 | 4 |
41 | 4 |
42 | 4 |
43 | 4 |
44 | 5 |
45 | 5 |
46 | 5 |
47 | 5 |
48 | 5 |
49 | 5 |
50 | 5 |
total | 158 |
1) mean job satisfaction=158/50 =3.16 ; as it is less than 4 whcih is equivalent to B (satisfied) ;
hence employees on average are not satisfied. they are Neither satisfied nor dissatisfied
2)
Median job satisfaction =(n+1)/2 th value =(50+1)/2 th value =25.5 th value =(3+3)/2 =3
which corresponds to C Neither satisfied nor dissatisfied
3)
Mode of job satisfaction =3 ; as it appears maximum numer of times (21)
4)25th percentile =npth value =50*0.25 th value =12.5 th value =3 ; equivalent to C
50th percentile = median =3 equivalent to C
75th percentile =npth value =50*0.75 th value =37.5 th value =4 ; equivalent to D