Question

In: Statistics and Probability

The meat department of a supermarket sells ground beef in approximate 1 lb packages, but there...

The meat department of a supermarket sells ground beef in approximate 1 lb packages, but there is some variability. A random sample of 65 packages yielded a mean of 1.05 lbs and a standard deviation of .23 lbs. What is the 95% Confidence Interval for this problem?

Group of answer choices

1 to 1.1

1.01 to 1.09

.99 to 1.11

.98 to 1.12

.98 to 1.12

Solutions

Expert Solution

s

olution :


Given that,

Point estimate = sample mean =     = 1.05

Population standard deviation =    = 0.23

Sample size n =65

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96   ( Using z table )

Margin of error = E =   Z/2    * ( /n)
= 1.96* ( .23 / 65)

= 0.06
At 95% confidence interval estimate of the population mean
is,

- E < < + E

1.05 - 0.06 <   < 1.05 + 0.06

0.99 to 1.11

orchestra answered 3 years ago
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