In: Biology
A population of 120 pea plants were examined. Three colorations existed within the population; 70 red (RR), 43 pink (Rr), and 7 white (rr). Calculate the 1) number of each allele and the 2) allele frequencies. Using the Hardy-Weinberg equilibrium equation (p2 +2pq+q2=1.0) calculate the 3) genotype frequencies. Based on a population size of 120 pea plants, 4) what is the predicted numbers of each genotype? 5) How does the predicted compare to the observed population? Show your work.
number of RR individuals =70 ,in this there is 70×2=140 R alleles.
Number of Rr individuals =43 ,in this there is 43×1=43 R alleles.and 43×1=43 r alleles.
Number of rr individuals =7 ,in this there is 7×2=14 r alleles.
1)So number of R alleles =140+43=183
Number of r alleles =43+14=57
2)here there are total of 2×70+2×43+2×7 =240 alleles.
So frequency of allele R=183/240 = 0.7625
Frequency of allele r= 57/240 = 0.2375.
3)here frequency of allele R = 0.7625
Frequency of allele r = 0.2375
So frequency of genotype RR = R×R= 0.7625×0.7625 = 0.5814
Frequency of genotype rr= r×r= 0.2375×0.2375= 0.0564
Frequency of genotype Rr = 2×R×r = 2×0.7625×0.2375= 0.3622
4)predicted number of each genotype are,
RR= 0.5814×120= 69.768
Rr= 0.3622×120= 43.464
rr=0.0564×120= 6.768
5)in predicted genotype in the number of RR individual and rr individuals there is a small decrease and small increase in Rr individuals. (But approximately it is same )