You are booking tickets for a flight to Brazil, the Cessna airplane only has 10 tickets....

You are booking tickets for a flight to Brazil, the Cessna airplane only has 10 tickets. It is common knowledge that only 85% of people who buy plane tickets actually make it to the gate, so the airline sells 11 tickets for your flight. What is the probability that there will be at least 1 empty seat?

Solutions

Expert Solution

P(at least 1 empty seat) = 1 - P(none of the seats are empty)

= 1 - P(greater than or equal to 10 people make it to the gate)

= 1 - [P(X = 10) + P(X = 11)]

= 1 - [11C10 * 0.85¹⁰ * 0.15¹ + 11C11 * 0.85¹¹ * 0.15⁰]

= 1 - 0.4922

= 0.5078

orchestra answered 1 year ago

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