Find inverse laplace transform of F(s)=(6s^3+120s^2 +806s+1884)/(s^2+10s+29)^2 please write detailed answer thanks in advance

Find inverse laplace transform of F(s)=(6s^3+120s^2 +806s+1884)/(s^2+10s+29)^2

please write detailed answer thanks in advance

Expert Solution

milcah answered 1 year ago

Find the inverse Laplace transform of a. F(s) = se-6s/(s-2)(s2+2s+1) b. F(s) = e-12s/s3(s2+4)

Find the inverse Laplace transform for 1 / ((s^2+1)(s+1))

find inverse laplace transform of F(s)= (2s³ +5s²+8s+22)/[(s²+4)(s²+3s+2)]

Express the inverse transform as an integral s(s+3)/[(s^2+4)(s^2+6s+10)]

1) Find the Laplace transform of f(t)=−(2u(t−3)+4u(t−5)+u(t−8)) F(s)= 2) Find the Laplace transform of f(t)=−3+u(t−2)⋅(t+6) F(s)=...

1) Find the Laplace transform of f(t)=−(2u(t−3)+4u(t−5)+u(t−8)) F(s)= 2) Find the Laplace transform of f(t)=−3+u(t−2)⋅(t+6) F(s)= 3) Find the Laplace transform of f(t)=u(t−6)⋅t^2 F(s)=

(a) Determine the inverse Laplace transform of F(s) =(2s−1)/s^2 −4s + 6 (b) Solve the initial...

(a) Determine the inverse Laplace transform of F(s) =(2s−1)/s^2 −4s + 6 (b) Solve the initial value problem using the method of Laplace transform. d^2y/dx^2 −7dy/dx + 10y = 0, y(0) = 0, dy/dx(0) = −3. (c) Solve the initial value problem: 1/4(d^2y/dx^2)+dy/dx+4y = 0, y(0) = −1/2,dy/dx(0) = −1.

inverse laplase transform problem F(s)= (7s+11)/s(s+5)((s^2)+4s+20) find F(t) using laplase transform

Please give a detailed explanation, not just the answer. Thanks in advance! Use the data in...

Please give a detailed explanation, not just the answer. Thanks in advance! Use the data in the given table to fill in the missing coefficients. Round your answers to 3 decimal places. x y 2 13.524 7.5 19.125 13 23.463 18.5 28.937 24 33.6 29.5 37.779 35 43.065 y=_____x +_______

Use a table to find the inverse Laplace transform h(t) of H(s). H(s) = 40s /((s2...

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Find the laplace transform of the following functions, using the definition of Laplace transforms: f(t)=-2cos4t f(t)=2...

Find the laplace transform of the following functions, using the definition of Laplace transforms: f(t)=-2cos4t f(t)=2 sin^2(t) g(t)=3e^tcos(t)

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