Question

In: Chemistry

A solution is prepared using a sodium salt of an unknown diprotic base. The unknown diprotic...

A solution is prepared using a sodium salt of an unknown diprotic base. The unknown diprotic weak base solution will be analyzed for concentration by titration with a strong acid. The unknown is placed in an Erlenmyer flask, and small, measured volumes of a standard strong acid solution are added until the final equivalence point is reached. Then the concentration of the base is calculated fromthe known volumes, the one known concentration and stoichiometry. All solutions are kept at room temperature.

A. Before the titration starts, is the solution in the flask acidic, neutral or alkaline?

B. Write a complete ionic equation for the complete (Bronsted-Lowry) acid-base neutralization reaction of a generic weak diprotic base B2- with hydrochloric acid.

C. List the most commonform of each solute species that is present in the reaction mixture at the final equivalence point, and label each as a strong acid, weak acid, neutral, weak base, or strong base.

D. At the final equivalence point, will the overall solution be strongly acidic, weakly acidic, neutral, weakly basic, or strongly basic?

E. List the solute species that are present when more standard is added after the final equivalence point, and label each as either a strong acid, weak acid, neutral, weak base or strong base.

F. If extra titrant is added tto the flask after the final equivalence point has been reached, will the mixture be strongly acidic, weakly acidic, neutral, weakly basic, or strongly basic?

Solutions

Expert Solution

Consider the salt to be Na2B.

A. The solution contains the weak base B2- , pH is basic.

B.   

B2- + 2HCl- = H2B + 2Cl-

C. At the final EP the solution contains H2B . By hydrolysis:

H2B         +        H2O =           HB-   +         HO-

H2B   weak acid

HB-   amphoter (weak base in the above reaction)

H2O neutral ( acid in the above reaction)

HO-   strong base

D. The solution contains the weak acid H2B. pH<7.

E. The solution contains the excess of HCl and H2B.

The species in solution are:

H3O+ strong acid

Cl- ineffective base

H2B weak acid, can be considered not dissociated in the presence of the strong acid (Le Chetelier principle, common ion effect).

F. The pH will be strongly acidic ( the solution contains HCl in excess).


Related Solutions

Sodium acetate (NaOAc) is the sodium salt of the conjugate base of acetic acid (HOAc). Although...
Sodium acetate (NaOAc) is the sodium salt of the conjugate base of acetic acid (HOAc). Although NaOAc is a strong electrolyte, the acetate ion itself (OAc−) is a weak base. Assume pKa = 4.76 for HOAc.a. (1 pt) Calculate the pH of a 50.0 mM HOAc solution. Using a 5% criterion, exp licitly check any approximations you make to ensure they are valid.b.(1 pt) Calculate the pH of a 50.0 mM NaOAc solution. Again, check your assumptions.
A solution of an unknown acid is prepared by dissolving 0.250 g of the unknown in...
A solution of an unknown acid is prepared by dissolving 0.250 g of the unknown in water to produce a total volume of 100.0 mL. Half of this solution is titrated to a phenolphthalein endpoint, requiring 12.2 mL of 0.0988 M KOH solution. The titrated solution is re-combined with the other half of the un-titrated acid and the pH of the resulting solution is measured to be 4.02. What is are the Ka value for the acid and the molar...
A solution is prepared by dissolving 11.6 g of a mixture of sodium carbonate and sodium...
A solution is prepared by dissolving 11.6 g of a mixture of sodium carbonate and sodium bicarbonate in 1.00 L of water. A 300.0 cm3sample of the solution is then treated with excess HNO3 and boiled to remove all the dissolved gas. A total of 0.940 L of dry CO2 is collected at 298 K and 0.972 atm. 1. Find the molarity of the carbonate in the solution. 2. Find the molarity of the bicarbonate in the solution.
An EDTA solution was prepared by dissolving the disodium salt in 1l of water. It was...
An EDTA solution was prepared by dissolving the disodium salt in 1l of water. It was standardized using 0.5063 gram of primary standard CaCO3 and consumed 28.50 ml of the solution. The standard solution was used to determine the hardness of a 2L sample of mineral water, which required 35.57 ml of EDTA solution. Express the analysis in terms of ppm CaCO3 ? Answers. 316 ppm
An acetic acid/ sodium acetate buffer solution was prepared using the following components: 3.46 g of...
An acetic acid/ sodium acetate buffer solution was prepared using the following components: 3.46 g of NaC2H3O2∙3H2O (FW. 136 g/mol) 9.0 mL of 3.0 M HC2H3O2 55.0 mL of water -What is the total volume of the solution? -Calculate the concentration of the [C2H3O2-] in this solution. -Calculate the concentration of the [HC2H3O2] in this solution. -Calculate the pH of this buffer solution. The Ka for acetic acid is 1.8x10-5. -If you take half of this solution and add 2...
An unknown mass of sodium hydroxide is dissolved in 500 g of water. This solution is...
An unknown mass of sodium hydroxide is dissolved in 500 g of water. This solution is neutralized by adding successively 18 g of CH3COOH, 25.2 g HNO3, and 29.4 g of H2SO4. Determine a) the mass of NaOH b) the mass of H2O in the neutral solution.
The pH at 25 °C of an aqueous solution of the sodium salt of β-naphthol (NaC10H7O)...
The pH at 25 °C of an aqueous solution of the sodium salt of β-naphthol (NaC10H7O) is 11.28. Calculate the concentration of C10H7O- in this solution, in moles per liter. Ka for HC10H7O is equal to 3.1×10-10.
We started with 200.0mL of an 0.08 M Solution of the sodium salt of valine. We...
We started with 200.0mL of an 0.08 M Solution of the sodium salt of valine. We then added 25.0mL of 1.00 M HBr. pka1= 2.286 pka2= 9.719 Ka1= 5.18x10^-3 Ka2= 1.91x10^-10 Please explain the solution and where it is based on the equivalence points! a) What is the new solution made? Be descriptive. b) What is the pH of the new solution?
An aqueous solution is prepared to be 0.243 M in sodium formate and 0.120 M in...
An aqueous solution is prepared to be 0.243 M in sodium formate and 0.120 M in benzoic acid. (1) Is this solution a buffer solution? (2) What is the pH of this solution? (3) If 0.124 moles of hydrobromic acid are added to one liter of this solution, what is the pH of the resulting solution? Ka value of benzoic acid = 6.3X10^-5
a 500.00 mL solution is prepared by dissoving 6.20 sodium acetate in water. the pKa of...
a 500.00 mL solution is prepared by dissoving 6.20 sodium acetate in water. the pKa of the conjugate acid (acetic acid) is 4.75. Calculate the solution pH and the concentration of acetate and acetic acid (in molarity mol/L). Use the molecular weight of sodium acetate of 82.0 g/mol.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT