Question

In: Statistics and Probability

A report in 2002 found that 21.1% of American adults smoked cigarettes. The town of San...

A report in 2002 found that 21.1% of American adults smoked cigarettes. The town of San Sebastian spent five years focusing on educating their population on the health risks associated with smoking cigarettes, and at the conclusion of this five-year campaign, a study of 1200 participants found that 17.1% of the respondents were current smokers. Is this evidence enough that the public-health campaign has lowered the proportion of smokers in San Sebastian? Use α = 0.02 (Show all steps please)

a)State the null and alternative hypothesis (H0 and Ha). H0: Ha:

b) What is the test statistic for this sample (use at least 3 decimal places)?

c) What is the p-value for this sample? (use Statcrunch)

d)Evaluate the strength of the evidence and state the conclusion (in the context of this question).

Solutions

Expert Solution

Let p denotes the true proportion of smokers in San Sebastian in recent times.

There is enough evidence to support the claim that the public-health campaign has lowered the proportion of smokers in San Sebastian.


Related Solutions

In a poll of 232 adults, it was found that 22% smoked cigarettes in the past...
In a poll of 232 adults, it was found that 22% smoked cigarettes in the past week. Test the claim that less than 25% of adults have smoked within the past week. Use 0.05 significance level Careful: You need to convert percent into decimals. (Round to 2 decimals) Ho : p = Ha : p < z - Test Statistic = (Round to 2 decimals) p - Value = (Round to 4 decimals) Conclusion: There is sufficient evidence to (support...
If is the fact that 13.7% of American adults smoke cigarettes. If 25 American adults were...
If is the fact that 13.7% of American adults smoke cigarettes. If 25 American adults were chosen at random, what is the probability that at most 7 of them smoked cigarettes?
Of 147 adults selected randomly in one town, it was found that 31 of them smoke....
Of 147 adults selected randomly in one town, it was found that 31 of them smoke. If we were to calculate a 95% confidence interval for the proportion of people in this town who smoke, what is the margin of error? Round to 3 decimal places.
You and your spouse have found your town home in San Marcos, CA. The selling price...
You and your spouse have found your town home in San Marcos, CA. The selling price is $360,000; you will put $60,000 down and obtain a 30–year fixed-rate mortgage at 7.25% for the rest. 3. Refer to above. Assume that monthly payments begin in one month. What will each payment be? A. $2,325.01 B. $2,046.53 C. $1,876.48 D. $1,938.72 E. $2,173.46 4. Refer to above. Although you will get a 30-year mortgage, you plan to prepay the loan by making...
A recent study found that the average credit score for employed American adults is 702.5. A...
A recent study found that the average credit score for employed American adults is 702.5. A credit analyst wonders if this number is actually different for working millenials. In a random sample of 15 employed millenials, their sample mean credit score was 715.2 with a sample standard deviation of 83. Assume that credit scores of the population are normally distributed. (a) Conduct the appropriate test to determine if millenials have a different credit score at the α = 0.05 level...
Confidence Intervals In a random sample of 1100 American adults it was found that 320 had...
Confidence Intervals In a random sample of 1100 American adults it was found that 320 had hypertension (high-blood pressure). The US Department of Health and Human Services (HHS) wants the population proportion of hypertension to 16% by 2022. Find the 95% confidence interval for the proportion of all adult Americans that have hypertension. Interpret the confidence interval in the words of the problem. Find the error bound. Does this data and analysis provide evidence that the population proportion of hypertension...
In the first week of November, 2005, the Gallup Organization surveyed 1000 American adults and found...
In the first week of November, 2005, the Gallup Organization surveyed 1000 American adults and found that 220 of them had smoked at least one cigarette in the past week.  In 1990 Gallup also asked 1000 American adults the same question in the first week of November and determined that 270 had smoked at least one cigarette in the previous week.  Is there significant evidence the proportion of American adults who smoked at least one cigarette in the previous week was less...
A Pew Internet & American Life study found that teens and young adults consider their frequent...
A Pew Internet & American Life study found that teens and young adults consider their frequent e-communication as very different from the traditional writing they learn in school and generally don’t consider it “real writing.” Although they are tech-smart, students don’t always understand the boundaries of acceptable media use and need to learn that employers expect more formal, thoughtful, informative, and error-free messages on the job. How would you deal with this in the workplace?
In May 2018, the Gallup surveyed 1,024 American adults and found that 60 percent believed abortion...
In May 2018, the Gallup surveyed 1,024 American adults and found that 60 percent believed abortion should be legal within the first trimester of pregnancy. In 1996, Gallup asked the same question among 550 adults and found that 64 percent believed abortion should be legal within the first trimester of pregnancy. a) Find the 95 percent confidence interval of the population proportion of adult Americans that support legal abortion within the first trimester of pregnancy in 2018. b) Using ?...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT