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In: Operations Management

Lindsay​ Electronics, a small manufacturer of electronicresearch​ equipment, has approximately 7 comma 100 items in...

Lindsay Electronics, a small manufacturer of electronic research equipment, has approximately 7 comma 100 items in its inventory and has hired Joan Blasco-Paul to manage its inventory. Joan has determined that 8% of the items in inventory are A items, 32% are B items, and 60% are C items. She would like to set up a system in which all A items are counted monthly (every 18 working days), all B items are counted quarterly (every 59 working days), and all C items are counted semiannually (every 121 working days). How many items need to be counted each day? The total number of items that need to be counted each day is nothing items (round your response to the nearest whole number).

Solutions

Expert Solution

Total number of items = 7100

A items = 8% of total = 7100*0.08 = 568

B items = 32% of total = 7100*0.32 = 2272

C items = 60% of total = 7100*0.6 = 4260

A items are counted monthly (every 18 working days). Hence daily counts = 568/18 = 31.56

B items are counted quarterly (every 59 working days). Hence daily counts = 2272/59 = 38.51

C items are counted semiannually (every 121 working days). Hence daily counts = 4260/121 = 35.21

Hence total daily counts = 31.56 + 38.51 + 35.21 = 105.28 = 105

keosha answered 2 years ago
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