Question

Using the data in the table, calculate the rate constant of this reaction.

A+B⟶C+DA+B⟶C+D

Trial	[?] (?)[A] (M)	[?] (?)[B] (M)	Rate (M/s)
1	0.4000.400	0.2000.200	0.01600.0160
2	0.4000.400	0.5400.540	0.1170.117
3	0.4800.480	0.2000.200	0.01920.0192

?=k=

Units

Answer 1

Answer

Trial	[A] in M	[B] in M	Rate M/s	Rate constant (dm3)5/2mol-5/2s-1
1	0.400	0.200	0.0160	0.2
2	0.400	0.540	0.117	0.5417
3	0.480	0.200	0.0192	0.2

Explanation

Rate of the reaction is First order with respect to [A]           [1.2 = 1.2/1.2 = 1]

Rate of the reaction is 5/2 order with respect to [B]             [2.7= 7.313/2.7    = 2.7 5/2]

Rate of the reaction is 7/2 with respect to both [A] and [B]. Unit for 7/2 rate constant is (dm³)^5/2mol^-5/2s^-1

Rate = Rate constant*[A]*[B]

Rate constant =

Trial 1

Rate constant =

Rate constant = 0.2 (dm³)^5/2mol^-5/2s^-1

Trial 2

Rate constant =

Rate constant = 0.5417 (dm³)^5/2mol^-5/2s^-1

Trial 3

Rate constant =

Rate constant = 0.2 (dm³)^5/2mol^-5/2s^-1