In: Statistics and Probability
Bayus (1991) studied the mean numbers of auto dealers visited by early and late replacement buyers. Letting μ be the mean number of dealers visited by all late replacement buyers, set up the null and alternative hypotheses needed if we wish to attempt to provide evidence that μ differs from 4 dealers. A random sample of 100 late replacement buyers yields a mean and a standard deviation of the number of dealers visited of x¯ = 4.37 and s = .56. Using a critical value and assuming approximate normality to test the hypotheses you set up by setting α equal to .10, .05, .01, and .001. Do we estimate that μ is less than 4 or greater than 4? (Round your answers to 3 decimal places.) H0 : μ (Click to select) 4 versus Ha : μ (Click to select) 4. t tα/2 = 0.05 tα/2 =0.025 tα/2 =0.005 tα/2 =0.0005 There is (Click to select) evidence. μ is (Click to select) 4.