In: Finance
Problem 1:
The following information is given about options on the stock of a certain company:
S0 = $80, X =$70, r =10% per year (continuously compounded), T = 9 months, s= 0.30
No dividends are expected. One option contract is for 100 shares of the stock. All notations are used in the same way as in the Black-Scholes-Merton Model.
Price of a European call option as per black sholes model os given by
C= S0× N(d1) - K×e-rt N(d2)
d1 = ( ln(S0/K) + (r + (σ2/2)) t ) / σ √t
d2 = ( ln(S0/K) + (r - (σ2/2)) t ) / σ √t = d1 - σ √t
where
C = price of call
S0= current stock price = 80
K= X= Strike price = 70
r= risk free rate= 10% continueous
t= T/12 = 9/12 = 3/4 = .75 year
= s= standard deviation = .30
In(S0/k)= ln(80/70)/(.30×(.75)^.5 )=.51396
( (r+s^2/2)t)/s×(t)^.5 = ((.10 +.30^2/2)×.75)/(.30×(.75)^.5
= .41858
d1= .51396 + .41858 = .93254
d2= d1 - s×(t)^.50 =.93254 - .30× (.75)^.5 = .67273
N(d1) = N(.93254) = is the cumulative normal distribution probability for z = .93254 as per normal distribution table this is .82447
And similarly N(.67273) = .74944
Therefore
C= 80× .82447 - 70 ×e^-(.10×.75)×.74944 = $17.29
Put price can be calculated by using put call perity PCP.
PCP is given by
C - P = S0 - K × e^(-rt)
17.29 -P =80 - 70 ×e^(-.10×.75)
P= $2.23 this is the put price
Part b
Protective put means buying a put and stock so that when the price price goes down put can protect the holder.
Payment for buying put = 2.23×100= 223
Payment for Buying share = 80 ×100 = 8000
Total cost = $8223
Covered call means selling a call long with buying stock
Amount received in selling call= 17.29×100 =$1729
Amounts paid to buy stock= 80×100=$8000
Total cost = 9729$
Part 3
Receivable Pay off of put = max((K-S),0)×m
Where S = different stock prices
m = lot size= 100
Pay off from stock= S×100
Profit = 100S - max((70 - S),0)×100 - 8223
Table is as follows
Call pay off payble= max((S-K),0)
stock payoff receivable= 100S
Profit = 100S- max((S-70),0)×100 -9729
Table is