Question

In: Statistics and Probability

Bob Nale is the owner of Nale’s Quick Fill. Bob would like to estimate the mean...

Bob Nale is the owner of Nale’s Quick Fill. Bob would like to estimate the mean number of gallons of gasoline sold to his customers. Assume the number of gallons sold follows the normal distribution with a population standard deviation of 2.30 gallons. From his records, he selects a random sample of 60 sales and finds the mean number of gallons sold is 8.60. What is the point estimate of the population mean? (Round your answer to 2 decimal places.) Develop a 99% confidence interval for the population mean. (Use z Distribution Table.) (Round your answers to 3 decimal places.)?

Solutions

Expert Solution

Solution :

Given that,

At 99% confidence level the z is ,

= 1 - 99% = 1 - 0.99 = 0.01

/ 2 = 0.01 / 2 = 0.005

Z/2 = Z0.005 = 2.576

Margin of error = E = Z/2* ( /n)

= 2.576 * (2.30 / 60)

= 0.765

At 99% confidence interval estimate of the population mean is,

- E < < + E

8.60 - 0.765 < < 8.60 + 0.765

7.835 < < 9.365

(7.835 , 9.365)


Related Solutions

Bob Nale is the owner of Nale’s Quick Fill. Bob would like to estimate the mean...
Bob Nale is the owner of Nale’s Quick Fill. Bob would like to estimate the mean number of gallons of gasoline sold to his customers. Assume the number of gallons sold follows the normal distribution with a population standard deviation of 1.90 gallons. From his records, he selects a random sample of 75 sales and finds the mean number of gallons sold is 5.40. a. What is the point estimate of the population mean? (Round your answer to 2 decimal...
Bob Nale is the owner of Nale’s Quick Fill. Bob would like to estimate the mean...
Bob Nale is the owner of Nale’s Quick Fill. Bob would like to estimate the mean number of gallons of gasoline sold to his customers. Assume the number of gallons sold follows the normal distribution with a population standard deviation of 2.50 gallons. From his records, he selects a random sample of 70 sales and finds the mean number of gallons sold is 7.80. What is the point estimate of the population mean? (Round your answer to 2 decimal places.)...
Bob Nale is the owner of Nale’s Quick Fill. Bob would like to estimate the mean...
Bob Nale is the owner of Nale’s Quick Fill. Bob would like to estimate the mean number of gallons of gasoline sold to his customers. Assume the number of gallons sold follows the normal distribution with a population standard deviation of 2.50 gallons. From his records, he selects a random sample of 55 sales and finds the mean number of gallons sold is 6.30. What is the point estimate of the population mean? (Round your answer to 2 decimal places.)...
Bob Nale is the owner of Nale’s Quick Fill. Bob would like to estimate the mean...
Bob Nale is the owner of Nale’s Quick Fill. Bob would like to estimate the mean number of gallons of gasoline sold to his customers. Assume the number of gallons sold follows the normal distribution with a population standard deviation of 2.00 gallons. From his records, he selects a random sample of 65 sales and finds the mean number of gallons sold is 9.10. a. What is the point estimate of the population mean? (Round your answer to 2 decimal...
Bob Nale is the owner of Nale's Quick Fill. Bob would like to estimate the mean...
Bob Nale is the owner of Nale's Quick Fill. Bob would like to estimate the mean number of gallons of gasoline sold to his customers. Assume the number of gallons sold follows the normal distribution with a population standard deviation of 2.2 gallons. From his records, he selects a random sample of 56 sales and finds the mean number of gallons sold is 8.07. (Round your answers to 2 decimal places.) (a) The point estimate of the population mean is...
Bob Nale would like to determine the mean number of gallons of gasoline sold to his...
Bob Nale would like to determine the mean number of gallons of gasoline sold to his customers. Assume the number gallons of gasoline sold is 2 gallons. From his records, he selects 64 samples and finds the mean is 9 gallons. Find the 95% confidence interval for the population mean.
You are an experienced small business owner who would like to become a franchisee of Quick...
You are an experienced small business owner who would like to become a franchisee of Quick Burger, a nationwide franchise of fast food restaurants. There are some Quick Burger restaurants in your area, but not so many that another franchise would be unprofitable. Before joining the franchise, you want to make sure that the essential terms are clear to both parties. Discuss potential issues you would need to resolve before entering into a franchise contract with Quick Burger.
The owner of a departmental store would like to estimate monthly gross revenues as a function...
The owner of a departmental store would like to estimate monthly gross revenues as a function of advertising expenditures. Historical data for randomly selected 8 months is given below (₹ in crores) Monthly revenue Television Advertising Newspaper advertising Monthly revenue Television Advertising Newspaper advertising 105 5 3.5 100 4 2 95 2 1.5 98 2.5 2.5 102 3 3.3 100 3.5 2.3 98 2.5 4.2 95 3 2.5 a. Derive a regression equation with amount of expenditure on television advertising...
The owner of Showtime Movie Theaters would like to estimate weekly gross revenue as a function...
The owner of Showtime Movie Theaters would like to estimate weekly gross revenue as a function of advertising expenditures. Historical data for a sample of eight weeks are as below: Week Weekly gross revenue ($1000s) TV Advertising ($1000s) Newspaper Advertising ($1000s) 1 96 5.0 1.5 2 90 2.0 2.0 3 95 4.0 1.5 4 92 2.5 2.5 5 95 3.0 3.3 6 94 3.5 2.3 7 94 2.5 4.2 8 94 3.0 2.5 Following are the regression results for the...
1. The owner of Showtime Movie Theaters, Inc. would like to estimate weekly gross revenue as...
1. The owner of Showtime Movie Theaters, Inc. would like to estimate weekly gross revenue as a function of advertising expenditures. Historical data for a sample of eight weeks follow. Weekly Gross Television Newspaper Radio Revenue Advertising Advertising Advertising ($1000s) ($1000s) ($1000s) ($1000s) 96 5 1.5 0.3 90 2 2 0.2 95 4 1.5 0.3 92 2.5 2.5 0.1 95 3 3.3 0.4 94 3.5 2.3 0.4 94 2.5 4.2 0.3 94 3 2.5 0.3 Is the estimated regression equation...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT