Question

Listed below are amounts​ (in millions of​ dollars) collected from parking meters by a security service company and other companies during similar time periods. Do the limited data listed here show evidence of stealing by the security service​ company's employees? Security Service Company: 1.3 1.6 1.5 1.6 1.6 1.3 1.7 1.6 1.5 1.6 Other Companies: 1.6 1.9 1.5 1.7 1.8 1.9 1.5 1.7 1.8 1.7 The coefficient of variation for the amount collected by the security service company is? The coefficient of variation for the amount collected by the other companies is

Answer 1

	x1	x1 -mean1	(x1 -mean1)2	x2	x2-mean 2	(x2-mean 2)2
	1.3	-0.23	0.0529	1.6	-0.11	0.0121
	1.6	0.07	0.0049	1.9	0.19	0.0361
	1.5	-0.03	0.0009	1.5	-0.21	0.0441
	1.6	0.07	0.0049	1.7	-0.01	0.0001
	1.6	0.07	0.0049	1.8	0.09	0.0081
	1.3	-0.23	0.0529	1.9	0.19	0.0361
	1.7	0.17	0.0289	1.5	-0.21	0.0441
	1.6	0.07	0.0049	1.7	-0.01	0.0001
	1.5	-0.03	0.0009	1.8	0.09	0.0081
	1.6	0.07	0.0049	1.7	-0.01	0.0001
Sum=	15.3		0.161	17.1		0.189
mean=	1.53		0.0161	1.71		0.0189
	The coefficient of variation for the		sd1=	sqrt(0.0161)
	amount collected by the security			0.126885775
	service company =	sd1/mean 1*100	sd2=	sqrt(0.0189)
						0.137477271
	cv1 =	8.2931879		The coefficient of variation for the
				amount collected by the other
				company =	sd2/mean 2*100
					cv2=	8.039606482