Question

An aqueous solution of C6H12O6 has a mole fraction of 0.0445 for C6H12O6 in water. Calculate the Molarity of the solution. The density of the solution is 1.09 g/mL

Answer 1

Here,

Mole fraction of C₆H₁₂O₆ = 0.0445

Assuming total 1 mole of the solution

Moles of water =1-0.0445 = 0.9555

We have,

Molar mass of water = 18 g/mole

Molar mass of C₆H₁₂O₆ =180 g/mole

Therefore,

Total mass of the solution = (18 x 0.9555) + (180 x 0.0445) = 25.209 g

Now, Density = Mass/Volume

Therefore,

Volume of the solution = Mass/Density = 25.209/1.09

                                                                = 23.1275229 mL = 0.02312 L

Molarity = 0.0445 g/0.02312 L = 1.924 M