In: Statistics and Probability
A distribution of values is normal with a mean of 60 and a standard deviation of 28. From this distribution, you are drawing samples of size 22. Find the interval containing the middle-most 60% of sample means: Enter your answer using interval notation. In this context, either inclusive or exclusive intervals would be acceptable. Your numbers should be accurate to 1 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
P(
< x) = 0.2
or, P((
-
)/(
)
< (x -
)/(
))
= 0.2
or, P(Z < (x - 60)/(28/))
= 0.2
or, (x - 60)/(28/)
= -0.842
or, x = -0.842 * (28/)
+ 60
or, x = 55.0
P(
> x) = 0.2
or, P((
-
)/(
)
> (x -
)/(
))
= 0.2
or, P(Z > (x - 60)/(28/))
= 0.2
or, P(Z < (x - 60)/(28/))
= 0.8
or, (x - 60)/(28/)
= 0.84
or, x = 0.84 * (28/)
+ 60
or, x = 65.0