In: Statistics and Probability
Use the information below for the following 3 questions A recent survey of 80 IU students and 60 Ball State students found that the percent of IU students who are part of Greek life is 18%, while the percent Ball State students who are part of Greek life is 15%. Find the 95% confidence interval for the difference between the proportion of IU students who are part of Greek life compared to Ball State students, i.e. LaTeX: D=p_{IU}-p_{Ball\:State} D = p I U − p B a l l S t a t e . [.0222 ; .0378] [-.0740 ; .1340] [-.1340 ; .0740] [-.0935 ; .1535] Flag this Question Question 13 1 pts Suppose you want to test for whether Greek participation is greater at IU than at Ball State. Which of the following would be the hypothesis test? LaTeX: \left(D=p_{IU}-p_{Ball\:State}\right) ( D = p I U − p B a l l S t a t e ) LaTeX: H_0 \colon D\ge0 ; H_A \colon D<0 H 0 : D ≥ 0 ; H A : D < 0 H 0 : D ≥ 0 ; H A : D < 0 LaTeX: H_0 \colon D=0 ; H_A \colon D\ne0 H 0 : D = 0 ; H A : D ≠ 0 H 0 : D = 0 ; H A : D ≠ 0 LaTeX: H_0 \colon D\ne0 ; H_A \colon D=0 H 0 : D ≠ 0 ; H A : D = 0 H 0 : D ≠ 0 ; H A : D = 0 LaTeX: H_0 \colon D\le0 ; H_A \colon D>0 H 0 : D ≤ 0 ; H A : D > 0 H 0 : D ≤ 0 ; H A : D > 0 Flag this Question Question 14 1 pts What is the test statistic for the difference between IU and Ball State Greek life participation, using the sample proportions found above? Recall:LaTeX: D=p_{IU}-p_{Ball\:State} D = p I U − p B a l l S t a t e (Round intermediate calculations to the third decimal) 0.471 -7.394 1.348 2.209
Solution
Let p1 and p2 represent the population proportion of IU students who are part of Greek life and Ball State students respectively.
Q1 : Confidence Interval
100(1 - α) % Confidence Interval for (p1 - p2) is:
[(p1hat – p2hat) ± MoE, …………………………………………………….. (1)
where
MoE = (Zα/2)√[phat(1 – phat){(1/n1) + (1/n2)}] ……………………………….. (2)
with
p1hat = (x/n1),
p2hat = (y/n2),
phat = (n1 p1hat + n2 p2hat)/( n1 + n2),
Zα/2 is the upper (α /2)% point of N(0, 1),
n1 and n2 being the two sample sizes.
So, 95% confidence interval for the difference between the proportion of IU students who are part of Greek life compared to Ball State students is: [- 0.0949, 0.1549) Fourth Option Answer 1
Details of calculations
| 
 n1  | 
 80  | 
| 
 n2  | 
 60  | 
| 
 x  | 
 14.4  | 
| 
 y  | 
 9  | 
| 
 p1hat  | 
 0.18  | 
| 
 p2hat  | 
 0.15  | 
| 
 phat  | 
 0.16714286  | 
| 
 α  | 
 0.05  | 
| 
 Zα/2  | 
 1.95996398  | 
| 
 MoE  | 
 0.12488798  | 
| 
 LB  | 
 -0.094888  | 
| 
 UB  | 
 0.154888  | 
Q2 : Test Hypotheses
Hypotheses:
Null H0 : p1 = p2 Vs HA : p1 > p2Answer 2
Q3 Test Statistic
Z = (p1hat – p2hat)/√[phat(1 - phat){(1/n1) + (1/n2)} = 0.471 First Option Answer 3
where p1hat and p2hat are sample proportions,
n1, n2 are sample sizes and
phat = {(n1 x p1hat) + (n2 x p2hat)}/(n1 + n2).
Details of calculations
| 
 n1  | 
 80  | 
| 
 n2  | 
 60  | 
| 
 x  | 
 14.4  | 
| 
 y  | 
 9  | 
| 
 p1hat  | 
 0.18  | 
| 
 p2hat  | 
 0.15  | 
| 
 phat  | 
 0.167142857  | 
| 
 Zcal =  | 
 0.470813262  | 
DONE