Question

In: Statistics and Probability

Following are observed frequencies. The null hypothesis is =:H0p1=, 0.30p2=, 0.35p3=, 0.05p4=, 0.05p50.25 Category 1 2...

  1. Following are observed frequencies. The null hypothesis is =:H0p1=, 0.30p2=, 0.35p3=, 0.05p4=, 0.05p50.25

Category

1

2

3

4

5

Observed

71

91

22

21

75

P-VALUE =_________

  1. For the following observed and expected frequencies:

Observed

31

39

37

34

37

42

Expected

22

29

34

30

28

36

P-VALUE =________

  1. Are you smarter than your older brother? In a study of birth order and intelligence, IQ tests were given to 18- and 19-year-old men to estimate the size of the difference, if any, between the mean IQs of firstborn sons and secondborn sons. The following data for 10 firstborn sons and 10 secondborn sons are consistent with the means and standard deviations reported in the article. Assume that the samples come from normal populations.

Firstborn

113.4

92.7

115.3

105.6

131.6

98.8

125.4

117.7

92.6

110.2



Secondborn

106.1

112.3

91.9

114.1

104

106.1

92.9

101.7

128.8

119.8

Ho = o2

H1 < o2

Left tailed test

CRITICAL VALUE =________

Solutions

Expert Solution

The null hypothesis is =:H0: p1= 0.30, p2 = 0.35, p3= 0.05, p4 = 0.05, p5 = 0.25

Category Observed Expected (O-E)^2/E
1 71 84 2.011905
2 91 98 0.5
3 22 14 4.571429
4 21 14 3.5
5 75 70 0.357143
Total 280 280 10.94048

P-value = 0.0272

Category observed Expected (O-E)^2/E
1 31 22 3.681818
2 39 29 3.448276
3 37 34 0.264706
4 34 30 0.533333
5 37 28 2.892857
6 42 36 1
Total 11.82099

= 11.82

P-value = 0.0370

sl no. First born second born
1 113.4 106.1
2 92.7 112.3
3 115.3 91.9
4 105.6 114.1
5 131.6 104
6 98.8 106.1
7 125.4 92.9
8 117.7 101.7
9 92.6 128.8
10 110.2 119.8
Total 1103.3 1077.7
Mean 110.33 107.77
sd 13.11683 11.43669047

test statistic is given by,

t = 0.415

Left tailed test.

Critical value, - 1.734 at level 0.05.

****If you have any queries or doubts please comment below. if you're satisfied please give a like. Thank you!


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