Question
In: Chemistry
Calculate the ph of 0.125M of NaAc
Calculate the ph of 0.125M of NaAc
Solutions
Expert Solution
The give compound is a salt of sodium acetate (CH3COO-Na+)
The Ka of acetic acid = 1.8 X 10^-5
So Kb of acetic acid = Kw / Ka = 10^-14 / 1.8X 10^-5 = 5.56 X 10^-10
It will dissociate as
CH3COONa => CH3COO- + Na+
Now
CH3COO- + H2O <------> CH3COO- + OH-
Initial 0.125 0 0
Change -x x x
Equilibrium 0.125-x x x
Kb = x^2 / (0.125-x)
x <<1 so will ignore in denominator
1.56 X 10^-10 = x^2 / 0.125
x^2 = 0.195 X 10^-10
x = 0.442 X 10^-5 = 4.42 X 10^-6 = [OH-]
pOH = -log[OH-] = -log[4.42 X 10^-6]
pOH = 5.35
pH = 14-5.35 = 8.65
queen_honey_blossom answered 1 year agoRelated Solutions
50.0ml of 0.125M HF is titrated with 0.100M NaOH. Calculate the pH after the addition of...
50.0ml of 0.125M HF is titrated with 0.100M NaOH. Calculate the
pH after the addition of
a) 0.00ml of NaOH
b) 15.00ml of NaOH
c) 31.25ml of NaOH
d) 60.00ml of NaOH
e) 62.50ml of NaOH
f) 70.00ml of NaOH
Calculate the pH of each of the solutions and the change in pH to 0.01 pH...
Calculate the pH of each of the solutions and the change in pH
to 0.01 pH units caused by adding 10.0 mL of 2.81-M HCl to 340. mL
of each of the following solutions. Change is defined as final
minus initial, so if the pH drops upon mixing the change is
negative.
a) water pH before mixing = Correct: Your answer is correct.
pH after mixing= Incorrect: Your answer is incorrect.
pH change = Incorrect: Your answer is incorrect.
b)...
Calculate the pH of each of the solutions and the change in pH to 0.01 pH...
Calculate the pH of each of the solutions and the change in pH
to 0.01 pH units caused by adding 10.0 mL of 2.64-M HCl to 690. mL
of each of the following solutions. Change is defined as final
minus initial, so if the pH drops upon mixing the change is
negative.
a) water pH before mixing =
pH after mixing=
pH change =
b) 0.152 M C2H3O21-
pH before mixing =
pH after mixing=
pH change =
c) 0.152...
Calculate the pH of each of the solutions and the change in pH to 0.01 pH...
Calculate the pH of each of the solutions and the change in pH
to 0.01 pH units caused by adding 10.0 mL of 3.01-M HCl to 630. mL
of each of the following solutions.
Change is defined as final minus initial, so if the pH drops
upon mixing the change is negative.
a) water
pH before mixing =
pH after mixing=
pH change =
b) 0.109 M
C2H3O21-
pH before mixing =
pH after mixing=
pH change =
c) 0.109...
Calculate the pH of each of the solutions and the change in pH to 0.01 pH...
Calculate the pH of each of the solutions and the change in pH
to 0.01 pH units caused by adding 10.0 mL of 3.90-M HCl to 350. mL
of each of the following solutions.
Change is defined as final minus initial, so if the pH drops
upon mixing the change is negative.
a) water
pH before mixing =
pH after mixing=
pH change =
b) 0.118 M
C2H3O21-
pH before mixing =
pH after mixing=
pH change =
c) 0.118...
Calculate the pH of each of the solutions and the change in pH to 0.01 pH...
Calculate the pH of each of the solutions and the change in pH
to 0.01 pH units caused by adding 10.0 mL of 3.78-M HCl to 440. mL
of each of the following solutions.
Change is defined as final minus initial, so if the pH drops
upon mixing the change is negative.
a) water
pH before mixing =
pH after mixing=
pH change =
b) 0.154 M
C2H3O21-
pH before mixing =
pH after mixing=
pH change =
c) 0.154...
Calculate the pH of each of the solutions and the change in pH to 0.01 pH...
Calculate the pH of each of the solutions and the change in pH
to 0.01 pH units caused by adding 10.0 mL of 3.78-M HCl to 440. mL
of each of the following solutions.
Change is defined as final minus initial, so if the pH drops
upon mixing the change is negative.
a) water
pH before mixing =
pH after mixing=
pH change =
b) 0.154 M
C2H3O21-
pH before mixing =
pH after mixing=
pH change =
c) 0.154...
Calculate the pH of each of the solutions and the change in pH to 0.01 pH...
Calculate the pH of each of the solutions and the change in pH
to 0.01 pH units caused by adding 10.0 mL of 3.63-M HCl to 440. mL
of each of the following solutions.
a.) .181 M C2H3O2 1-
ph before mixing: 9.00 (correct)
pH after mixing: ??
b.) a buffer solution that is 0.181 M in each C2H3O2 1- and
HC2H3O2
pH before mixing: ??
pH after mixing: ??
Thank you!! Sincerely, a confused college student
Calculate the pH of each of the solutions and the change in pH to 0.01 pH...
Calculate the pH of each of the solutions and the change in pH
to 0.01 pH units caused by adding 10.0 mL of 3.35-M HCl to 550. mL
of each of the following solutions.
Change is defined as final minus initial, so if the pH drops
upon mixing the change is negative.
a) water
pH before mixing =
pH after mixing=
pH change =
b) 0.134 M
C2H3O21-
pH before mixing =
pH after mixing=
pH change =
c) 0.134...
Calculate the pH of each of the solutions and the change in pH to 0.01 pH...
Calculate the pH of each of the solutions and the change in pH
to 0.01 pH units caused by adding 10.0 mL of 2.05-M HCl to 570. mL
of each of the following solutions.
a) water
before mixing = 7
After mixing = 1.45
b) 0.135 M
C2H3O21-
Before mixing = 8.95
After mixing = ?
c) 0.135 M HC2H3O2
Before mixing = ?
After mixing = ?
d) a buffer solution that is 0.135 M in each
C2H3O21- and...
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- Compare the MOSFET, JFET , and BJT and identify the reasons these devices behave differently. What...
- How would you use SAS Enterprise Miner to create a neural network model of your example?
- Explain the use of neural networking modeling in predictive analytics.
- Current Market Mix of Netflix, as detail as possible, please.
- This is all one question, thank you so much in advance! You must evaluate a proposal...
- X Company is considering the purchase of a new processor that costs $200,000. Shipping and setup...
- There are a large number of tasks involved in information technology and programming, and many of...
ADVERTISEMENT