In: Mechanical Engineering
The cylindrical coordinate robot on a factory’s assembly line is shown in a top view (Figure P4.2). The 50-N force acts on a workpiece being held at the end of the robot’s arm. Express the 50-N force as a vector in terms of unit vectors i and j that are aligned with the x- and y-axes.
Figure P4.2
Angle made by the force with the horizontal is,
θ = 70° - 30°
= 40°
Find the force vector using the following relation,
Fi = (-F cos θ)i + (F sin θ)j
Here, the force acting is F.
Substitute, 50 N for F and 40° for θ in the equation,
F = (-F cos θ)i + (F sin θ)j
= (-50 × cos 40°)i + (50 × sin 40°)j
= (38.3 N)i + (32.14 N)j
= (-38.3i + 32.14j) N
Force vector acting on the arm is obtained as (-38.3i + 32.14j)N.
Force vector acting on the arm is obtained as (-38.3i + 32.14j)N.