Question

In: Statistics and Probability

It is known that the average age of someone in the NFL is 26.2 years old....

  1. It is known that the average age of someone in the NFL is 26.2 years old. Suppose we take a sample of 15 athletes and find that the average age is 26.8 years old with a sample standard deviation of 3.22 years. We are interested in testing if the average age of NFL players is increasing.
    1. Using the sample of 15 players, what would the 95% confidence interval be for the population mean?
    2. What are the null and alternative hypotheses?
    3. What is the critical value at 95% confidence?
    4. Calculate the test statistic.
    5. Find the p-value
    6. What conclusion would be made here at the 95% confidence level?
    7. Would my conclusion change if I changed alpha to .10? Show reasoning

Solutions

Expert Solution


Related Solutions

The average age of students at INTI International University is known to be 22.5 years old....
The average age of students at INTI International University is known to be 22.5 years old. Assume the population is normally distributed with a standard deviation of 5 years. Find the probability that the mean age of a sample of 64 students is between 20.9 and 23.8 years old.
World class marathon runners are known to run that distance (26.2 miles) in an average of...
World class marathon runners are known to run that distance (26.2 miles) in an average of 146 minutes with a standard deviation of 15 minutes. If we sampled a group of world class runners from a particular race, find the probability of the following: **(use 4 decimal places)** a.) The probability that one runner chosen at random finishes the race in less than 140 minutes. b.) The probability that 10 runners chosen at random have an average finish time of...
World class marathon runners are known to run that distance (26.2 miles) in an average of...
World class marathon runners are known to run that distance (26.2 miles) in an average of 146 minutes with a standard deviation of 15 minutes. If we sampled a group of world class runners from a particular race, find the probability of the following: **(use 4 decimal places)** a.) The probability that one runner chosen at random finishes the race in less than 140 minutes. b.) The probability that 10 runners chosen at random have an average finish time of...
World class marathon runners are known to run that distance (26.2 miles) in an average of...
World class marathon runners are known to run that distance (26.2 miles) in an average of 146 minutes with a standard deviation of 14 minutes. If we sampled a group of world class runners from a particular race, find the probability of the following: **(use 4 decimal places)** a.) The probability that one runner chosen at random finishes the race in less than 140 minutes. b.) The probability that 10 runners chosen at random have an average finish time of...
World class marathon runners are known to run that distance (26.2 miles) in an average of...
World class marathon runners are known to run that distance (26.2 miles) in an average of 143 minutes with a standard deviation of 13 minutes. If we sampled a group of world class runners from a particular race, find the probability of the following: **(use 4 decimal places)** a.) The probability that one runner chosen at random finishes the race in less than 137 minutes. b.) The probability that 10 runners chosen at random have an average finish time of...
The average retirement age in America is 64 years old. Do small business owners retire at a different average age?
  The average retirement age in America is 64 years old. Do small business owners retire at a different average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 57, 65, 50, 57, 65, 63, 63, 59, 54, 66, 53, 51, 68 What can be concluded at the αα = 0.01 level of significance? For this study, we should use:  t-test for a...
Assume the average age of an MBA student is 34.9 years old with a standard deviation...
Assume the average age of an MBA student is 34.9 years old with a standard deviation of 2.5 years. ​a) Determine the coefficient of variation. ​b) Calculate the​ z-score for an MBA student who is 29 years old. ​c) Using the empirical​ rule, determine the range of ages that will include 99.7​% of the students around the mean. ​d) Using​ Chebyshev's Theorem, determine the range of ages that will include at least 91​% of the students around the mean. ​e)...
ESPN believed that the average age of Sportszone visitors was 29 years old. To test this...
ESPN believed that the average age of Sportszone visitors was 29 years old. To test this hypothesis, it collected audience profile data at the ESPN SportsZone Web site and found that a typical user of the website was 25 years of age (i.e., sample mean = 25) with a standard deviation of 5. Assume that this sample value was based on a sample of 400 users. Test its hypothesis using 99% confidence level.
The instructor claims that the average age of his students is 30 years old. To test...
The instructor claims that the average age of his students is 30 years old. To test this claim a sample of 33 students is taken. At an alpha level of .05 is there enough evidence to support this instructors claim? Sample ages: 32,28,24,18,35,41,27,28,28,31,27,25,28,31,35,40,36,32,29,28,19,21,26,24,21,19,27,26,23,27,30,20,21 Please list null and alternate hypothesis, critical value, test value, and all steps towards rejecting or accepting the null hypothesis.
Assume the average age of an MBA student is 30.7 years old with a standard deviation...
Assume the average age of an MBA student is 30.7 years old with a standard deviation of 2.2 years. ​a) Determine the coefficient of variation. ​b) Calculate the​ z-score for an MBA student who is 26 years old. ​c) Using the empirical​ rule, determine the range of ages that will include 95​% of the students around the mean. ​d) Using​ Chebyshev's Theorem, determine the range of ages that will include at least 94​% of the students around the mean. ​e)...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT