mearth=5.9742×10^24kg rearth=6.3781×10^6 m mmoon=7.36×10^22kg rmoon=1.7374×10^6m death to moon=3.844×10^8m center to center G=6.67428×10^-11 1700 kg satellite is...

mearth=5.9742×10^24kg
rearth=6.3781×10^6 m
mmoon=7.36×10^22kg
rmoon=1.7374×10^6m
death to moon=3.844×10^8m center to center
G=6.67428×10^-11

1700 kg satellite is orbiting the Earth in a circular orbit with an altitude of 1700 km
1) how much energy does it take to get it to this altitude
2)how much kinetic energy does it have once it has reached this altitude
3)what is the ratio of this change in potential energy to change in kinetic energy
4)what would this ratio be if the final altitude of the satellite was 4700 km
5)what would be this ratio if the final altitude was 3185 km?

Expert Solution

genius_generous answered 1 year ago

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