Question

In: Statistics and Probability

(a) You wish to estimate the mean percentage price change for all supermarkets in the Foodmart...

(a) You wish to estimate the mean percentage price change for all supermarkets in the Foodmart chain. From the sample of 150 stores, we have calculated the sample mean,

x = 4.092 and sample standard deviation, s = 0.795.
(i) Calculate the 99% confidence interval estimate of the mean percentage change

for all supermarkets in the Foodmart chain.

(ii) Provide a plain language interpretation of the interval you have just constructed.

(iii) Nationally, the Food component of the Australian CPI increased by 3.9% for the year to June 2008. From your earlier results, does it appear that food price changes at Foodmart are any different to those as a nation overall? Explain your reasoning.

Solutions

Expert Solution

i) Since the population standard deviation is unknown, hence we would use the t-statistics to calculate the estimate of the mean percentage change.

The sample mean = 4.092

Sample standard deviation = 0.795

Degree of freedom = 150- 1 = 149

Significance level = 0.01

t-critical = 2.609

99% confidence interval estimate of the mean percentage change

ii) Interpretation: If we take many samples of size 150 and calculate the percentage price change for each of the samples then in 99% of the cases, the mean percentage change in price will lie in the interval [3.923, 4.261].

iii) A national percentage price change of 3.9% lies outside of the 99% confidence interval that we just calculated. Hence, the food price changes at Foodmart are different from those as a nation overall.

Alternatively,

The null hypothesis is that the mean percentage price change is the same for food mart to the national value.

There is a probability of 0.99 that a price change percentage will lie in the calculated given interval. So, there is a probability of less than 0.01 that a price change percentage will lie outside that interval. Since 3.9% lies outside that interval hence, the p-value for a price change percentage of 3.9 will be less than 0.01. If the p-value if less than 0.01 then we cannot accept the null hypothesis. Hence, the food price changes at Foodmart are different from those as a nation overall.

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