Why does the Zaitsev product always form in an E1 reaction regardless of the bulkiness of the base?
In: Chemistry
A 110.0-mL aliquot of 0.120 M weak base B (pKb = 4.55) was titrated with 1.20 M HClO4. Find the pH at the following volumes of acid added: Va = 0.00, 1.30, 5.50, 10.00, 10.90, 11.00, 11.10, and 14.00 mL. (Assume Kw = 1.01 ✕ 10−14.)
In: Chemistry
The dibasic compound B (pKb1 = 4.03, pKb2 = 8.06) was titrated with 1.12 M HCl. The initial solution of B was 0.112 M and had a volume of 100.0 mL. Find the pH at the following volumes of acid added: Va = 0.00, 2.00, 5.00, 9.00, 10.00, 11.00, 15.00, 19.00,20.00, and 22.00 mL. (Assume Kw = 1.01 ✕ 10−14.)
In: Chemistry
Consider N2O4 (g) ---> 2 NO2 (g) . 3.00 X 10-2 mol of N2O4 are placed in a 1.0 L flask. AT equilibrium, 2.36 X 10-2 mol of N2O4 remain. What is the Keq for this reaction?
In: Chemistry
A 23.7 mL sample of 0.355 M ammonia, NH3, is titrated with 0.329 M hydrochloric acid. At the equivalence point, the pH is .
In: Chemistry
Description: In week 1 we discussed which amino acids were termed “essential” but we lacked the knowledge to really understand why these would be difficult to make. Now that we have examined the process of making amino acids, let's take a second look at why the body doesn’t make certain amino acids.
Instructions: Write a response to the following prompt and then review your peers response:
Prompt: Propose a reason for why so many of the essential amino acids belong in the aliphatic and aromatic groups.
In: Chemistry
how does the rotameter (flow meter) measure volumetric flow rate of air in the system?explain using a digram and 2-3 sentence discussion of the forces acting on the rotameter ball.
In: Chemistry
KBr crystallizes in a NaCl (B1) structure with a lattice
constant of a=0.65966nm.
Determine the bulk density of KBr and the distance between a K ion
and a touching Br
ion in the structure. Rationalize your result with the sum of ionic
radii for K and Br
In: Chemistry
A solution is prepared by dissolving 15.0 g of pure HC2H3O2 and 25.0 g of NaC2H3O2 in 775 mL of solution (the final volume). (a) What is the pH of the solution? (b) What would the pH of the solution be if 25.0 mL of 0.250 M NaOH were added? (c) What would the pH be if 25.0 mL of 0.40 M HCl were added to the original 775 mL of buffer solution?
In: Chemistry
Classify the following ionic compounds according to the Sigma-Aldrich solubility scale based on their molar solubility (S).
Answer choices are: Very Soluble, Freely Soluble, Soluble, Sparingly Soluble, Slightly Soluble, Very Slightly Soluble, and Practically Insoluble.
a) Silver nitrite (AgNO2), S = 0.27 M. Answer is
b) Lithium Phosphate (Li3PO4), S = 3.4 x 10-3 M. Answer is
c) Aluminum Fluoride (AlF3), S = 8.6 x 10-2 M. Answer is
d) Tin (II) Iodide (SnI2), S = 2.9 x 10-2 M. Answer is
In: Chemistry
what is the chemical equation for the formation of eugenol from DCM and anyhydrous sodium sulfate?
In: Chemistry
Two isomeric compounds, A and B, are known to each have a monosubstituted benzene ring (C6H5). Both have the formula C6H5C3H5O2 and both are insoluble in water. However, when they are treated with an aqueous solution of sodium carbonate, A dissolves, but B does not. Give structures for both A and B consistent with this information. Explain your reasoning. Is the information provided sufficient to uniquely define the structures of A and B? If not, what other experimental data would be useful to further limit the structural possibilities? I really need to understand this really soon please answer as soon as possible.
In: Chemistry
A titration is performed by adding .435M KOH to 80ml of .205M HC3H5O2.
A) Calculate the pH before the addition of any KOH?
B) Calculate the pH after the addition of 7.54ml of KOH?
C) Calculate the volume of base needed to reach the equivalence point?
D) Enter the pH of the solution at the equivalence point of the titration?
In: Chemistry
What are the forms / pools of K in the soil? Which two pools constitute the available K to the plant in a growing season? Discuss briefly the relationship between these two pools.
In: Chemistry
For the last step in your potential Nobel-prize winning cancer cure drug you need 3-cyclopentyl-1-phenylhexan-3-ol, but no chemical company sells this particular alcohol. You, being the wonderful synthetic chemist that you are, figure you can make this tertiary alcohol from the simple Grignard reagent reaction you learned in your CH223 course.
A) Draw the structure of your target alcohol. Use the name to make sure you have the correct number of carbons:
B) If the Grignard reagent contains the aromatic ring, draw both
the appropriate Grignard reagent and carbonyl compound
(not an ester) you would need to make your target
molecule. Input the Grignard reagent first, then click the "New"
tool to allow the carbonyl compound input.
C) If the Grignard reagent contains the five-membered ring, draw
both the appropriate Grignard reagent and carbonyl compound
(not an ester) you would need to make your target
molecule. Input the Grignard reagent first, then click the "New"
tool to allow the carbonyl compound input.
D) There is one more combination that you could use to arrive at
the targent alcohol. Input the Grignard reagent first, then click
the "New" tool to allow the carbonyl compound (not
an ester) input of this last possible synthetic scheme.
In: Chemistry