In: Statistics and Probability
Approximately 22% of the daytime students at TCU are majoring in one of the four science colleges. If we were to take a random sample of 200 TCU students, what is the probability of getting a value for the sample proportion (p-hat) that is less than 0.20?
Solution
Given that,
p = 22%=0.22
1 - p = 1-0.22=0.78
n = 200
= p =0.22
= [p ( 1 - p ) / n] = [(0.22*0.78) / 200 ] = 0.029
P( < 0.20) =
= P[( - ) / < (0.20-0.22) / 0.029]
= P(z < -0.69)
Using z table,
=0.2451
probability =0.2451