The Mars candy company claims that the percentage of blue M&Ms [2] candies is 24%. A...

The Mars candy company claims that the percentage of blue M&Ms [2] candies is 24%. A sample of 200 M&Ms candies was selected and 54 candies were blue.

a) State the null hypothesis and the alternative hypothesis.

b) Test the claim using a significance level of 0.05.

c) State your conclusion. Should the Mars company take corrective action?

Expert Solution

( a )

Null and Alternative Hypotheses

The following null and alternative hypotheses need to be tested:

Ho :p =0.24

Ha :p ≠0.24

( b )

( c ) Conclusion :

It is concluded that the null hypothesis Ho is not rejected. Therefore is enough evidence to claim that the percentage of blue M&Ms [2] candies is 24% . at the α = 0.05 significance level.Therefore yes the Mars company take corrective action

orchestra answered 2 years ago

Mars, Inc. states that 24% of its M&M plain candies are blue and that 16% are...

Mars, Inc. states that 24% of its M&M plain candies are blue and that 16% are green. Assume that they are correct and a large random sample of plain M&Ms is randomly selected from the factory. A. What is the probability that if twenty M&Ms were eaten randomly from the sample, that exactly four of them would be green? B. Find the mean and standard deviation for the above binomial probability distribution in part c. Based on that, would it...

Q: The mars company claims that 13 percent of M&Ms plain candies distributed into bags are...

Q: The mars company claims that 13 percent of M&Ms plain candies distributed into bags are brown. Investigate this claim with an appropriate hypothesis test. Use a significance level of a= 0.05 Color Count Brown 33 Non-Brown 242 Total 275 1. The p-value for this test statistic is: _______________. 2. Null Hypothesis: 3. Alternative Hypothesis: 4. Conclusion: We REJECT/DO NOT REJECT the null hypothesis. (Circle the correct answer) State what this conclusion means in terms of the problem. 5. Would...

In 1995 the Mars Company replaced tan M&Ms with blue M&Ms. A sample of 100 plain...

In 1995 the Mars Company replaced tan M&Ms with blue M&Ms. A sample of 100 plain M&Ms before the introduction of blue M&Ms had a mean weight 0.9160g with a standard deviation of 0.0433g. A sample of 100 plain M&Ms taken after 1995 had a mean weight of 0.9147g and a standard deviation of 0.0369g. (a) Construct the 98% confidence interval for the difference in the mean weight of plain M&Ms before and after the introduction of blue M&Ms. List:...

Mars Inc., makers of M & M's candies, claims that they produce plain M & M's...

Mars Inc., makers of M & M's candies, claims that they produce plain M & M's with the following distribution Brown: 30% Red: 20% Yellow: 20% Orange: 10% Green: 1096 Blue: 10% A bag of plain M & M's was randomly selected trom the grocery store shelf, and the color counted were as follows Brown: 16 Red: 11Yellow: 19 Orange: 5 Green: 7 Blue: 3 How many total M & Ms were in this sample (This is your n)? What...

A few years ago, Mars sold M&Ms inspired by candy corn. The M&Ms in those bags...

A few years ago, Mars sold M&Ms inspired by candy corn. The M&Ms in those bags came in three colors: white, yellow, and orange. The following table shows the distributions of those colors in a bag of 90 M&Ms purchased at a local store.A few years ago, Mars sold M&Ms inspired by candy corn. Using an alpha of 0.05, carry out a goodness-of-fit test for the null hypothesis that the three colors appear equally often. (Hint: We will not be...

A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue,...

A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 yellow. Three candies are pulled from the bag in succession, without replacement. Determine the probability of the following. (Enter your probabilities as fractions.) -The first candy drawn is red. -The second candy drawn is red, given that the first candy drawn is red. -The third candy drawn is green, given that the first two candies drawn...

According to Mars, Inc., 20% of all M&Ms produced are blue. One bag of 50 M&Ms...

According to Mars, Inc., 20% of all M&Ms produced are blue. One bag of 50 M&Ms represents the sample for this problem. The sample data can be used to perform a two-sided hypothesis test to test whether 20% of all M&Ms are blue. In one bag of 50 M&Ms, there are 14 blue M&Ms. Use this data to test whether 20% of all M&Ms are blue.

A candy company claims that their packages typically have 50 red candies, 40 yellow candies, 25...

A candy company claims that their packages typically have 50 red candies, 40 yellow candies, 25 blue candies, 25 brown candies, and 10 orange candies. A study looked at a package, where it was found that the average package has 48 red candies, 42 yellow candies, 20 blue candies, 26 brown candies, and 14 brown candies. Do these observations contradict the company’s claim? Use a significant level of 0.05.

A candy company claims that the proportions of lemon, lime, cherry, and grape candies in its...

A candy company claims that the proportions of lemon, lime, cherry, and grape candies in its fruit-flavored candy bags are equal. A random sample of 500 candies gave the following results: 138 lemon, 114 lime, 130 cherry, and 118 grape. Use a significance level of 0.05 to test the claim that the proportions are what the candy company states. (Remember to state the null and alternative hypotheses, p-value, conclusion about the null hypothesis and final conclusion that addresses the original...

1. The Jupiter Candy Company claims their Good and Colorful candies are distributed by color as...

1. The Jupiter Candy Company claims their Good and Colorful candies are distributed by color as follows: Turquoise: 12%; Maroon: 21%; Chartreuse: 28%; Burnt Sienna: 14%; Eggshell: 25% A random sample of 200 G and C’s resulted in the following counts: Turquoise: 20; Maroon: 45; Chartreuse: 40; Burnt Sienna: 32; Eggshell: 63 Test whether the candies follow the given distribution at the level of significance (α) of 0.05

Question