In: Chemistry
Calculate the [H+], [OH-], pH, pOH for the resulting solution if 20.00 mL sample of 0.2650 M NaOH was titrated with 21.33 mL of 0.1175 M H2SO4.
H2SO4 NaOH
MA = 0.1175M MB = 0.2650M
VA = 21.33ml VB = 20ml
M = MBVB-MAVA/VA + VB
= 0.2650*20-0.1175*21.33/21.33+20
= 2.793725/41.33 = 0.0676M
M = [OH^-] = 0.0676M
[H^+] = Kw/[OH^-]
= 1*10^-14/(0.0676) = 1.48*10^-13M
POH = -log[OH^-]
= -log0.0676
= 1.17
PH = 14-POH
= 14-1.17 = 12.83