Question

In: Accounting

CB Electronics must buy a piece of equipment to place electronic components on the printed circuit boards it assembles. The proposed equipment has a 10-year life with no scrap value

CB Electronics must buy a piece of equipment to place electronic components on the printed circuit boards it assembles. The proposed equipment has a 10-year life with no scrap value.

The supplier has given CB several purchase alternatives. The first is to pay $175,000 now and $100,000 at the end of each year for the next 10 years. The second is to pay for the equipment in 10 equal installments of $140,000 each, starting one year from now. The third is to pay $725,000 now.

i) Which alternative should CB choose if their MARR is 15% per year? Use an IRR comparison approach.

ii) Below what MARR does it make sense for CB to buy the equipment now for $725,000?

Solutions

Expert Solution

i) Which alternative should CB choose if their MARR is 15% per year? Use an IRR comparison approach.

ANSWER

CB should accept the first alternative.

 

WORKING

PV of first alternative = $175,000 + $100,000(P/F, 15%, 10) = $175,000 + $100,000(6.145) = $175,000 + $614,500 = $789,500

 

PV of second alternative = $140,000(P/A, 15%, 10) = $140,000(6.145) = $855,430

 

PV of third alternative = $725,000(P/F, 15%, 1) = $725,000(0.8696) = $632,380

 

IRR of first alternative = 20.74%

IRR of second alternative = 20.47%

IRR of third alternative = 15.00%

The first alternative has the highest IRR and should be accepted.

 

ii) Below what MARR does it make sense for CB to buy the equipment now for 

$725,000?

ANSWER

The equipment should be bought now for $725,000 when the MARR is 13.64% per year.

 

WORKING

PV of first alternative = $175,000 + $100,000(P/F, MARR, 10) = $175,000 + $100,000(6.145) = $175,000 + 

$614,500 = $789,500

 

PV of second alternative = $140,000(P/A, MARR, 10) = $140,000(6.145) = $855,430

 

PV of third alternative = $725,000(P/F, MARR, 1) = $725,000(0.8696) = $632,380

 

IRR of first alternative = 20.74%

IRR of second alternative = 20.47%

IRR of third alternative = 15.00%

 

The third alternative should be accepted when the MARR is 13.64% per year.


Related Solutions

A piece of equipment cost $1,000, has a salvage value of $100, and a 5-year life....
A piece of equipment cost $1,000, has a salvage value of $100, and a 5-year life. Use this information for questions 2-8.   2. Depreciation expense per year using the straight line method is A. $180 B. $200 C. $500 D. $240 3. Using the straight line method, what is accumulated depreciation after 3 years? A. $600 B. $480 C. $400 D. $540 4. Using Sum-of-the-Years' Digits, depreciation expense is A. $333 B. $500 C. $300 D. $240 5. Using Sum-of-the-Years'...
An investor is planning to buy an asset which will cost ksh 8,000,000. The asset has a useful life of 10 years and will have a scrap value of 700,000 at the end of the tenth year.
An investor is planning to buy an asset which will cost ksh 8,000,000. The asset has a useful life of 10 years and will have a scrap value of 700,000 at the end of the tenth year. There is a 55% chance that the asset will bring in additional revenue of 15,000,000 per year and a 45% chance that the asset will bring in additional revenue of 5,000,000 per year for eight years and will incur additional costs of 900,000...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT