In: Statistics and Probability
A local band has two albums of material that they play at concerts. Their first album contains 11 songs and their second album contains 10 songs. The band is to select 3 songs at to play as an opener for a nationally touring band. If the songs are chosen at random, what is the probability that the selection of 3 songs will include at least one song from their second album?
Total songs available = 11 + 10 = 21
Number of ways to choose 3 songs from 21 = 21C3 = 21! / (3! * (21 - 3)!) = 1330
P(at least one song from their second album) = P(0 song from their second album)
= 11C3 / 21C3
= 165 / 1330
= 0.1241