Question

In: Biology

The following pedigree shows a person affected with the sex chromosome aneuploidy called Klinefelter syndrome (XXY)....

The following pedigree shows a person affected with the sex chromosome aneuploidy called Klinefelter syndrome (XXY). Recall that human aneuploidy is caused by nondisjunction during meiosis. A and B are two codominant alleles of an x linked gene; the phenotypes of individuals for this x linked gene are shown. In which parent of the affected person did nondisjuction occur, and was the nondisjuction event in meiosis I or II? Check all that are possible.

- Father; Meiosis I

- Father; Meiosis II

- Mother; Meiosis I

- Mother; Meiosis II

Solutions

Expert Solution

FAILURE OF SEGREGATION OF CHROMATIDS DURING CELL DIVISION CYCLE RESULTS IN THE GAIN OR LOSS OF CHROMOSOSMES. THIS IS CALLED ANEUPLOIDY.

KLINFELTERS SYNDROME IS A GENETIC DISORDER CAUSED DUE TO THE PRESENCE OF AN ADDITIONAL COPY OF X CHROMOSOME RESULTING IN TO A KARYOTYPE OF 47 XXY INSTEAD OF 46 XY OR 46 XX.SUCH INDIVIDUALS ARE STERILE.

THE EXTRA CHROMSOME IS DUE TO THE NON DISJUNCTION DURING MEOSIS 1 .MEOSIS 1 IS AGAIN DIVIDED IN TO PROPHASE 1 , METAPHASE 1 , ANAPHASE 1 AND TELOPHASE 1.

DURING PROPHASE 1 CROSSING OVER OCCURS BETWEEN NON SISTER CHROMATIDS ONE PATERNAL CHROMOSOSME AND ONE MATERNAL CHROMOSOME.

DURING METAPHASE 1 CHROMOSOEMS ALIGN AT THE EQUITORILA PLATE.

DURING ANAPHASE 1 EACH DIAD   IS  PULLED TOWARDS THE OPPOSITE POLES  OF THE DIVIDING CELL. THIS SEPERATION PROCESS IS KNOWN AS DISJUNCTION . ANY FAILURE IN THIS SEPERATION PROCESS RESULTS IN NONDISJUNCTION .

DURING TELOPHASE 1 CELL DIVIDES IN TO TWO.

NONDISJUNCTION RESULTS IN MOVING OF TWO CHROMTIDS TO A SINGLE CELL INSTEAD OF MOVING IN TO SEPERATE CELLS. THIS NONDISJUNCTION MAY OCCUR IN SPERM OR EGG . THAT IS BOTH MOTHER AND FATHER HAVE EQUAL CHANCES OF NONDISJUNCTION DURING MEOSIS 1.

EVENTS IN MEOSIS 2 IS JUST LIKE MITOSIS . MEOSIS 2 IS KNOWN AS EQUATIONAL DIVISION. NONDISJUNCTION DOESNOT OCCUR DURING MEOSIS 2

SO THE NONDISJUNCTION MAY OCCURED IN FATHER DURING MEOSIS 1 OR IN MOTHER DURING MEOSIS 1.


Related Solutions

List the normal pair of sex chromosomes, and possible sex chromosome aneuploidy for male and female,...
List the normal pair of sex chromosomes, and possible sex chromosome aneuploidy for male and female, respectively. And then briefly explain the possible mechanism of XY girls and XX boys.
Fragile X syndrome is a sex-linked disease that leads to intellectual impairment in affected individuals. Explain...
Fragile X syndrome is a sex-linked disease that leads to intellectual impairment in affected individuals. Explain the mutation that leads to fragile X syndrome. How does the number of repeats affect gene expression?
If a person was hung upside down, how would the following be affected compared to when...
If a person was hung upside down, how would the following be affected compared to when the person was standing up straight? a) Stroke Volume b) ANP release c) Na reabsorption d) Diuresis e) Sympathetic activation
Write a Java class called Person. The class should have the following fields: A field for...
Write a Java class called Person. The class should have the following fields: A field for the person’s name. A field for the person’s SSN. A field for the person’s taxable income. A (Boolean) field for the person’s marital status. The Person class should have a getter and setter for each field. The Person class should have a constructor that takes no parameters and sets the fields to the following values: The name field should be set to “unknown”. The...
Refactor the following classes so they are both derived from a base class called Person. Write...
Refactor the following classes so they are both derived from a base class called Person. Write the code for the new base class as well. Try to avoid repeating code as much as possible. Write the classes so that any common methods can be invoked through a pointer or reference to the base class. #include <string> #include <cmath> using namespace std; class Student { private: string name;    int age;    int studyYear; public:    Student(string,int,int); void study();    void...
The following table shows data on average per capita (per person) wine consumption and heart disease...
The following table shows data on average per capita (per person) wine consumption and heart disease rate in a random sample of 10 countries. Yearly wine consumption in liters Death from heart disease 2.5 221 3.9 167 2.9 131 2.4 191 2.9 220 0.8 297 9.1 71 2.7 172 0.8 211 0.7 300 1. Compute a correlation coefficient (r) between these two variables and interpret it. 2. H0 and Ha hypothesis 3.t statistic 4. p value 5.Does the data provide...
The following hypothetical reaction shows a neutron (n) decaying into a proton (p+), an electron (e−), and an uncharged particle called an antineutrino
The following hypothetical reaction shows a neutron (n) decaying into a proton (p+), an electron (e−), and an uncharged particle called an antineutrino: At first there is no charge, but then charge seems to be “created.” Does this reaction violate the law of charge conservation? Explain.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT