1a) Bizarrely enough, male fruitfly spermatocytes do not undergo any crossing over (True fact!). Only female...

1a) Bizarrely enough, male fruitfly spermatocytes do not undergo any crossing over (True fact!). Only female oocytes are capable of recombination. Given this fact, If A and B are 42 map units apart on the same chromosome, and a male fly with AB and ab chromosomes mates with a female having AB and ab chromosomes, what will the genotypic offspring ratios be (2 points)? I understand that they must be linked because the recombination frequency is less than 50% here. -they are on the same chromosome.

1b) What will the phenotypic offspring ratios be, assuming A encodes apricot eyes, and is dominant to white eyes (a), and B encodes bristly legs, and is dominant to smooth legs (b)

1c) What will the genotypic ratios be if the female fly has chromosomes AB and aB, and the male has AB and ab chromosomes?

Solutions

Expert Solution

Phenotypic ratio -

A_B_ = apricot bristly = 58.41

A_bb = apricot smooth = 16.59

aaB_ = white bristly = 16.59

aabb = white smooth = 8.41

C. Genotypic ratio -

AABB = 8.41

AABb = 6.09 + 6.09 = 12.18

AaBb = 6.09 + 6.09 = 12.18

AaBb = 8.41 + 8.41 + 4.41 + 4.41 = 25.64

AaBB = 6.09 + 6.09 = 12.18

aaBB = 4.41

AAbb = 4.41

aabb = 8.41

aaBb = 4.41 + 6.09 = 10.50

Please rate high.

gladiator answered 1 year ago

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