In: Statistics and Probability
Noise levels at 6 airports were measured in decibels yielding the following data: 137,132,145,152,209,169
Construct the 80% confidence interval for the mean noise level at such locations. Assume the population is approximately normal.
Step 3 of 4 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Step 4 of 4: Construct the 80% confidence interval. Round your answer to one decimal place. Lower endpoint Upper endpoint
We have for given data,
Sample mean =157.33
Sample standard deviation =28.43
Sample size =6
Level of significance=1-0.80=0.2
Degree of freedom =
5
t critical value is (by using t table)= 1.476
Confidence interval formula is
=(140.2,174.5)
Lower confidence limit= 140.2
Upper confidence limit= 174.5