Question

A study of identity theft looked at how well consumers protect themselves from this increasingly prevalent crime. The behaviors of 63 college students were compared with the behaviors of 58 nonstudents. One of the questions was "When asked to create a password, I have used either my mother's maiden name, or my pet's name, or my birth date, or the last four digits of my social security number, or a series of consecutive numbers." For the students, 24 agreed with this statement while 29 of the nonstudents agreed.

(a) Display the data in a two-way table.

	Students		Nonstudents		Total
Agreed
Disagreed
Total					121

Perform the chi-square test. (Round your χ² to three decimal places and round your P-value to four decimal places.)

χ2	=
df	=
P-value	=

Summarize the results.

We can conclude at the 5% level that students and nonstudents differ in the response to this question.We cannot conclude at the 5% level that students and nonstudents differ in the response to this question.   

(b) Reanalyze the data using the methods for comparing two proportions that we studied in the previous chapter. Compare the results and verify that the chi-square statistic is the square of the z statistic. (Test students who agreed minus nonstudents who agreed. Round your z to two decimal places and round your P-value to four decimal places.)

z	=
P-value	=

(c) The students in this study were junior and senior college students from two sections of a course in Internet marketing at a large northeastern university. The nonstudents were a group of individuals who were recruited to attend commercial focus groups on the West Coast conducted by a lifestyle marketing organization. Discuss how the method of selecting the subjects in this study relates to the conclusions that can be drawn from it.

Answer 1

		c1	c2	total
	r1	24	29	53
	r2	39	29	68
	total	63	58	121
	Oi	24	29	39	29
	Ei	27.59504	25.40496	35.40495868	32.59504
						TS
	(O--Ei)^2/Ei	0.468357	0.508732	0.365042711	0.396512	1.738644
	critical value	3.84
	p-value	0.187311

a)

	Students		Nonstudents		Total
Agreed	24		29		53
Disagreed	39		29		68
Total	63		58		121

X^2 = 1.739

df= 1

p-value = 0.1873

since p-value > alpha

we fail to reject the null hypothesis

We cannot conclude at the 5% level that students and nonstudents differ in the response to this question.   

b)

	x	n	p
1	24	63	0.380952
2	29	58	0.5

TS	-1.32
p-value
2-tail	0.1873

z = -1.32

p-value = 0.1873

c)

The students were selected were doing course in Internet marketing at a large northeastern university. The nonstudents were a group of individuals who were recruited to attend commercial focus groups on the West Coast conducted by a lifestyle marketing organization. So, both groups are educated enough to know the pros and cons of identity theft. So, proportion of students and nonstudents who agree/disagree with the statements may be approximately identical.

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