In: Statistics and Probability
A life insurance company wants to estimate its annual payouts. Assume that the probability distribution of the lifetimes of the participants is approximately a normal distribution with a mean of 68 years and a standard deviation of 4 years. What proportion of the participants die before they reach the age of 65?
mean = = 68
standard deviation = = 4
P(X< 65) = P[(X- ) / < (65-68) /4 ]
= P(z <-0.75 )
Using z table
= 0.2266
proportion=0.2266