Question

In: Statistics and Probability

The rising cost of malpractice insurance is a growingproblem. A random sample of thirty-three General...

The rising cost of malpractice insurance is a growing problem. A random sample of thirty-three General Surgery claims from TN had a mean cost of $47505 with a standard deviation of $1535.

a.     Find a 95% confidence interval for the mean claim amount of all General Surgery claims in TN.

b.     Interpret the confidence interval in the words of the problem.

c.      Find the error bound.

d.     A senator claims that mean for all General Surgery claims in TN is more than $45000. Is there evidence to support or refute this claim? Justify!

Solutions

Expert Solution

given data are :-

sample mean () = 47505

sample sd (s) = 1535

sample size (n ) = 33

a). df = (n-1) = (33-1) = 32

t critical value for 95% confidence level, both tailed test be:-

[ using t distribution table, for df = 32, alpha= 0.05 , both tailed test]

the 95% confidence interval for the mean claim amount of all General Surgery claims in TN is:-

b).interpretation:-

we are 95% confident that the mean for all General Surgery claims in TN will be within $46961 and $ 48049.

c).the error bound is:-

d).yes, there is sufficient evidence to support the claim that mean for all General Surgery claims in TN is more than $45000.

because all the values (upper limit and lower limit) of the 95% confidence interval is greater than 45000.


Related Solutions

Confidence Intervals The rising cost of malpractice insurance is a growing problem. A random sample of...
Confidence Intervals The rising cost of malpractice insurance is a growing problem. A random sample of thirty-three General Surgery claims from TN had a mean cost of $47505 with a standard deviation of $1535. Find a 95% confidence interval for the mean claim amount of all General Surgery claims in TN. Interpret the confidence interval in the words of the problem. Find the error bound. A senator claims that mean for all General Surgery claims in TN is more than...
5. Thirty percent of the employees of a large company are minorities. A random sample of...
5. Thirty percent of the employees of a large company are minorities. A random sample of 8 employees is selected. (Total: 7 marks; a-c: 2 marks each, d: 1 mark) a. What is the probability that the sample contains exactly 7 minorities? b. What is the probability that the sample contains less than 5 minorities? c. What is the probability that the sample contains exactly 1 non-minority? d. What is the expected number of minorities in the sample
If a physician is fully insured by malpractice insurance against payment to a victim of malpractice,...
If a physician is fully insured by malpractice insurance against payment to a victim of malpractice, is there any consequence to the physician for delivering care that was below the prevailing standard of care? Discuss this in the context of accountability.
The following data represent the Intelligence Quotient Scores of a random sample of thirty adults. ...
The following data represent the Intelligence Quotient Scores of a random sample of thirty adults.  Construct a Stem-and-Leaf Plot AND a Five Number Summary for the measurements.  Compute the locator of the median, the median, AND the mean of the thirty measurements. Sample of Size n = 30 108 100 103 125 108 90 122 89 96 99 100 84 121 129 91 103 90 106 75 98 102 89 99 82 90 100 120 114 93 104
Thirty five percent of adult Americans are regular voters. A random sample of 350 adults in...
Thirty five percent of adult Americans are regular voters. A random sample of 350 adults in a medium size college town were surveyed, and it was found that 155were regular voters. Estimate the true proportion with 95% confidence and comment on your results.Write a conclusion for the confidence interval.Round to 3 decimalplaces.
A random sample found that thirty-eight percent of 50 Americans were satisfied with the gun control...
A random sample found that thirty-eight percent of 50 Americans were satisfied with the gun control laws in 2017. Compute a 90% confidence interval for the true proportion of Americans who were satisifed with the gun control laws in 2017. Fill in the blanks appropriately. A 90% for the true proportion of Americans who were satisfied with the gun control laws in 2017 is ( , ) (Keep 3 decimal places)
Patsy Pennypincher is very concerned with the rising cost of education. She collected a sample of...
Patsy Pennypincher is very concerned with the rising cost of education. She collected a sample of 20 institutions (n=20) and found a sample mean cost of $15,500 (mean = 15,500) and a sample standard deviation to be $3000 (s = 3000). Provide Patsy with a 98% confidence interval for this year’s tuition cost. Please show your work.
A random sample of thirty dash nine ​200-meter swims has a mean time of 3.95 minutes...
A random sample of thirty dash nine ​200-meter swims has a mean time of 3.95 minutes and the population standard deviation is 0.08 minutes. Construct a 90​% confidence interval for the population mean time. Interpret the results. The 90​% confidence interval is
A random sample of thirty-six 200-meter swims has a mean time of 3.009 minutes. The population...
A random sample of thirty-six 200-meter swims has a mean time of 3.009 minutes. The population standard deviation is 0.080 minutes. A 90​% confidence interval for the population mean time is (2.987,3.031). Construct a 90​% confidence interval for the population mean time using a population standard deviation of 0.04 minutes. Which confidence interval is​ wider? Explain.
With the rising cost of home insurance, Danilo is thinking about switching insurers. He currently pays...
With the rising cost of home insurance, Danilo is thinking about switching insurers. He currently pays NRMA $28.78 per week. If he was to switch to Allianz, Danilo can choose between paying his insurance premium either at the beginning of the year or the beginning of the fortnight. If the annual premium with Allianz is $2,682.74, what fortnightly payment would be corresponding to paying annually given an interest rate of 8% p.a. compounded weekly?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT