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Voyager 1 space probe transmits to Earth at a frequency of 6.2 GHz. At some point...

Voyager 1 space probe transmits to Earth at a frequency of 6.2 GHz. At some point the intensity of the wave was I = 2.95e-25 W / m2.
a) What will be the intensity of the wave at half the distance from the space probe?

b) What is the wavelength of the transmitted signal?

If the power of the sun is 3.87e + 26 W.

c) At what distance from the sun, the radiation intensity will be 0.393 W / m2?

e) If we consider the previous distance as the Voyager 1 distance to the earth. And that the power of the antenna is 18 W. What will be the intensity of the wave transmitted by Voyager 1 that reaches the earth?

f) How many times farther is the Voyager 1 probe from the beginning of the problem?

Need a,b,c,d,e and f. Thanks!

Solutions

Expert Solution

Is this complete question ????

Intensity at what point is 2.95e-25 ??

anyway. intensity varies as

I = 1/r2

______________________________________________

What is the wavelength of the transmitted signal?

wavelength = speed of light / frequency

wavelength = 3e8 / 6.2e9

wavelength = 0.04838 m

__________________________________

At what distance from the sun, the radiation intensity will be 0.393 W / m2

assuming the sun is an isotropic source ( which it is )

I = power / area

area = power / intensity

4r2 = power / intensity

4r2 = 3.87e26 / 0.393

solve for r, we get

r = 8.852e12 meters ( mind the units , please !!!)

______________________________________________

If we consider the previous distance as the Voyager 1 distance to the earth. And that the power of the antenna is 18 W. What will be the intensity of the wave transmitted by Voyager 1 that reaches the earth

Here antenna is not treated as isotropic source because I think it is always pointed towards earth

Intensity = 18 / pi * 8.852e122

Intensity = 7.312e-26 W/m2

__________________________________________

genius_generous answered 2 years ago
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