Question

In: Chemistry

Here's the measurements from my expirement. (reaction 1) 0.502 g Cu (s) 4.0 mL HNO3 100...

Here's the measurements from my expirement.
(reaction 1)
0.502 g Cu (s)
4.0 mL HNO3
100 mL DI water

(reaction 2)
30 mL 3.0 M NAOH

(reaction 3)
nothing was added.

(reaction 4)
200 mL of DI water
15 mL of 6.0 M HCl

(reaction 5)
2.003 g Zn
10 mL 6M HCl
5 mL methanol
5 mL DI water
43.492 g mass of evaporating dish
44.549 g mass of evaporating dish with solid

Here are the reactions:
reaction 1: theoretical mass of copper (II) nitrate formed
Cu+4HNO3-->Cu(NO3)2+2NO2+2H2O

reactoin 2: theoretical mass of copper (II) hydroxide formed
Cu(NO3)2+2NaOH-->Cu(OH)2+2NaNO3

reaction 3: theoretical mass of copper (II) oxide formed
Cu(OH)2-->CuO+H2O

reaction 4: theoretical mass of copper (II) sulfate formed
CuO+H2SO4-->CuSO4+H2O

reaction 5: theoretical mass of copper formed
Zn+CuSO4-->ZnSO4+Cu

Can somebody show me how to work the first one at least, so then maybe I can figure the rest out. I just do not know where to start.

Expert Solution

queen_honey_blossom answered 1 year ago

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