A 10 g ice cube at 0oC is melted in 100 g water initially at 20oC....

A 10 g ice cube at 0^oC is melted in 100 g water initially at 20^oC. The equilibrium temperature of the mixture is 10.93^oC.

Calculate:

a) The heat lost by the water.

b) The heat gained by the melted water of the ice cube.

c) The heat absorbed by the ice to achieve melting.

Solutions

Expert Solution

A:- a) The heat lost by the water is calculated as,

Equilibrium temperature of the mixture = 10.93^oC.

Initially temperature of water = 20^oC,

The heat lost by the water = 4.184 joules * 100 g * 20-10.93

= 4.184 joules * 100 g * 9.07^oC

= 3794.89 joules

b) The heat gained by the melted water of the ice cube = 4.184 joules * 10 g * 9.07^oC

= 436.63 joules

c) The heat absorbed by the ice to achieve melting = 4.184 joules * 10 g * 9.07^oC

= 436.63 joules

queen_honey_blossom answered 1 year ago

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