A 10 g ice cube at 0oC is melted in 100 g water initially at 20oC....

A 10 g ice cube at 0^oC is melted in 100 g water initially at 20^oC. The equilibrium temperature of the mixture is 10.93^oC.

Calculate:

a) The heat lost by the water.

b) The heat gained by the melted water of the ice cube.

c) The heat absorbed by the ice to achieve melting.

Expert Solution

A:- a) The heat lost by the water is calculated as,

Equilibrium temperature of the mixture = 10.93^oC.

Initially temperature of water = 20^oC,

The heat lost by the water = 4.184 joules * 100 g * 20-10.93

= 4.184 joules * 100 g * 9.07^oC

= 3794.89 joules

b) The heat gained by the melted water of the ice cube = 4.184 joules * 10 g * 9.07^oC

= 436.63 joules

c) The heat absorbed by the ice to achieve melting = 4.184 joules * 10 g * 9.07^oC

= 436.63 joules

queen_honey_blossom answered 2 years ago

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