Question

In: Math

Find the solution set of the linear system: {█(■( x_1+x_4=260 -x_3+x_4+x_5=-200 x_2+x_3=300 x_1-x_2-x_5=150

Find the solution set of the linear system: {█(■(

x_1+x_4=260

-x_3+x_4+x_5=-200

x_2+x_3=300

x_1-x_2-x_5=150

Solutions

Expert Solution

augmented matrix is

1 0 0 1 0 260
0 0 -1 1 1 -200
0 1 1 0 0 300
1 -1 0 0 -1 150

convert into Reduced Row Eschelon Form...

Add (-1 * row1) to row4

1 0 0 1 0 260
0 0 -1 1 1 -200
0 1 1 0 0 300
0 -1 0 -1 -1 -110


Swapping row3 with row2

1 0 0 1 0 260
0 1 1 0 0 300
0 0 -1 1 1 -200
0 -1 0 -1 -1 -110


Add (1 * row2) to row4

1 0 0 1 0 260
0 1 1 0 0 300
0 0 -1 1 1 -200
0 0 1 -1 -1 190


Divide row3 by -1

1 0 0 1 0 260
0 1 1 0 0 300
0 0 1 -1 -1 200
0 0 1 -1 -1 190


Add (-1 * row3) to row4

1 0 0 1 0 260
0 1 1 0 0 300
0 0 1 -1 -1 200
0 0 0 0 0 -10


Divide row4 by -10

1 0 0 1 0 260
0 1 1 0 0 300
0 0 1 -1 -1 200
0 0 0 0 0 1


Add (-200 * row4) to row3

1 0 0 1 0 260
0 1 1 0 0 300
0 0 1 -1 -1 0
0 0 0 0 0 1


Add (-300 * row4) to row2

1 0 0 1 0 260
0 1 1 0 0 0
0 0 1 -1 -1 0
0 0 0 0 0 1


Add (-260 * row4) to row1

1 0 0 1 0 0
0 1 1 0 0 0
0 0 1 -1 -1 0
0 0 0 0 0 1


Add (-1 * row3) to row2

1 0 0 1 0 0
0 1 0 1 1 0
0 0 1 -1 -1 0
0 0 0 0 0 1

reduced system is

from last column equation is

which is not possible

hence system has no solution


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