In: Math
Find the solution set of the linear system: {█(■(
x_1+x_4=260
-x_3+x_4+x_5=-200
x_2+x_3=300
x_1-x_2-x_5=150

augmented matrix is
| 1 | 0 | 0 | 1 | 0 | 260 | 
| 0 | 0 | -1 | 1 | 1 | -200 | 
| 0 | 1 | 1 | 0 | 0 | 300 | 
| 1 | -1 | 0 | 0 | -1 | 150 | 
convert into Reduced Row Eschelon Form...
Add (-1 * row1) to row4
| 1 | 0 | 0 | 1 | 0 | 260 | 
| 0 | 0 | -1 | 1 | 1 | -200 | 
| 0 | 1 | 1 | 0 | 0 | 300 | 
| 0 | -1 | 0 | -1 | -1 | -110 | 
Swapping row3 with row2
| 1 | 0 | 0 | 1 | 0 | 260 | 
| 0 | 1 | 1 | 0 | 0 | 300 | 
| 0 | 0 | -1 | 1 | 1 | -200 | 
| 0 | -1 | 0 | -1 | -1 | -110 | 
Add (1 * row2) to row4
| 1 | 0 | 0 | 1 | 0 | 260 | 
| 0 | 1 | 1 | 0 | 0 | 300 | 
| 0 | 0 | -1 | 1 | 1 | -200 | 
| 0 | 0 | 1 | -1 | -1 | 190 | 
Divide row3 by -1
| 1 | 0 | 0 | 1 | 0 | 260 | 
| 0 | 1 | 1 | 0 | 0 | 300 | 
| 0 | 0 | 1 | -1 | -1 | 200 | 
| 0 | 0 | 1 | -1 | -1 | 190 | 
Add (-1 * row3) to row4
| 1 | 0 | 0 | 1 | 0 | 260 | 
| 0 | 1 | 1 | 0 | 0 | 300 | 
| 0 | 0 | 1 | -1 | -1 | 200 | 
| 0 | 0 | 0 | 0 | 0 | -10 | 
Divide row4 by -10
| 1 | 0 | 0 | 1 | 0 | 260 | 
| 0 | 1 | 1 | 0 | 0 | 300 | 
| 0 | 0 | 1 | -1 | -1 | 200 | 
| 0 | 0 | 0 | 0 | 0 | 1 | 
Add (-200 * row4) to row3
| 1 | 0 | 0 | 1 | 0 | 260 | 
| 0 | 1 | 1 | 0 | 0 | 300 | 
| 0 | 0 | 1 | -1 | -1 | 0 | 
| 0 | 0 | 0 | 0 | 0 | 1 | 
Add (-300 * row4) to row2
| 1 | 0 | 0 | 1 | 0 | 260 | 
| 0 | 1 | 1 | 0 | 0 | 0 | 
| 0 | 0 | 1 | -1 | -1 | 0 | 
| 0 | 0 | 0 | 0 | 0 | 1 | 
Add (-260 * row4) to row1
| 1 | 0 | 0 | 1 | 0 | 0 | 
| 0 | 1 | 1 | 0 | 0 | 0 | 
| 0 | 0 | 1 | -1 | -1 | 0 | 
| 0 | 0 | 0 | 0 | 0 | 1 | 
Add (-1 * row3) to row2
| 1 | 0 | 0 | 1 | 0 | 0 | 
| 0 | 1 | 0 | 1 | 1 | 0 | 
| 0 | 0 | 1 | -1 | -1 | 0 | 
| 0 | 0 | 0 | 0 | 0 | 1 | 
reduced system is

from last column equation is

which is not possible
hence system has no solution