In: Math
Find the solution set of the linear system: {█(■(
x_1+x_4=260
-x_3+x_4+x_5=-200
x_2+x_3=300
x_1-x_2-x_5=150
augmented matrix is
1 | 0 | 0 | 1 | 0 | 260 |
0 | 0 | -1 | 1 | 1 | -200 |
0 | 1 | 1 | 0 | 0 | 300 |
1 | -1 | 0 | 0 | -1 | 150 |
convert into Reduced Row Eschelon Form...
Add (-1 * row1) to row4
1 | 0 | 0 | 1 | 0 | 260 |
0 | 0 | -1 | 1 | 1 | -200 |
0 | 1 | 1 | 0 | 0 | 300 |
0 | -1 | 0 | -1 | -1 | -110 |
Swapping row3 with row2
1 | 0 | 0 | 1 | 0 | 260 |
0 | 1 | 1 | 0 | 0 | 300 |
0 | 0 | -1 | 1 | 1 | -200 |
0 | -1 | 0 | -1 | -1 | -110 |
Add (1 * row2) to row4
1 | 0 | 0 | 1 | 0 | 260 |
0 | 1 | 1 | 0 | 0 | 300 |
0 | 0 | -1 | 1 | 1 | -200 |
0 | 0 | 1 | -1 | -1 | 190 |
Divide row3 by -1
1 | 0 | 0 | 1 | 0 | 260 |
0 | 1 | 1 | 0 | 0 | 300 |
0 | 0 | 1 | -1 | -1 | 200 |
0 | 0 | 1 | -1 | -1 | 190 |
Add (-1 * row3) to row4
1 | 0 | 0 | 1 | 0 | 260 |
0 | 1 | 1 | 0 | 0 | 300 |
0 | 0 | 1 | -1 | -1 | 200 |
0 | 0 | 0 | 0 | 0 | -10 |
Divide row4 by -10
1 | 0 | 0 | 1 | 0 | 260 |
0 | 1 | 1 | 0 | 0 | 300 |
0 | 0 | 1 | -1 | -1 | 200 |
0 | 0 | 0 | 0 | 0 | 1 |
Add (-200 * row4) to row3
1 | 0 | 0 | 1 | 0 | 260 |
0 | 1 | 1 | 0 | 0 | 300 |
0 | 0 | 1 | -1 | -1 | 0 |
0 | 0 | 0 | 0 | 0 | 1 |
Add (-300 * row4) to row2
1 | 0 | 0 | 1 | 0 | 260 |
0 | 1 | 1 | 0 | 0 | 0 |
0 | 0 | 1 | -1 | -1 | 0 |
0 | 0 | 0 | 0 | 0 | 1 |
Add (-260 * row4) to row1
1 | 0 | 0 | 1 | 0 | 0 |
0 | 1 | 1 | 0 | 0 | 0 |
0 | 0 | 1 | -1 | -1 | 0 |
0 | 0 | 0 | 0 | 0 | 1 |
Add (-1 * row3) to row2
1 | 0 | 0 | 1 | 0 | 0 |
0 | 1 | 0 | 1 | 1 | 0 |
0 | 0 | 1 | -1 | -1 | 0 |
0 | 0 | 0 | 0 | 0 | 1 |
reduced system is
from last column equation is
which is not possible
hence system has no solution