In: Statistics and Probability
A random sample of ten professional athletes produced the following data. The first row is the number of endorsements the athlete has and the second row is the amount of money made (in millions of dollars) by the athlete. If a professional athlete did 6 endorsements, what could they expect to profit according to the regression equation? Round to one decimal point.
Number of Endorsements |
0 |
3 |
2 |
1 |
5 |
5 |
4 |
3 |
0 |
4 |
Profit (in Millions) |
2 |
8 |
7 |
3 |
13 |
12 |
9 |
9 |
3 |
10 |
Solution:
We can use the excel regression data analysis tool to find the answer to the given questions. The excel steps are:
Enter the data in excel.
Click on Data > Data analysis > Regression > Ok
Input Y range: Select all the data under Number of Endorsements including label
Input X range: Select all the data under Profit (in Millions) including label
Mark the labels
Choose the output range and the output is given below:
SUMMARY OUTPUT | ||||||
Regression Statistics | ||||||
Multiple R | 0.979 | |||||
R Square | 0.958 | |||||
Adjusted R Square | 0.952 | |||||
Standard Error | 0.836 | |||||
Observations | 10 | |||||
ANOVA | ||||||
df | SS | MS | F | Significance F | ||
Regression | 1 | 126.805 | 126.805 | 181.311 | 0.000 | |
Residual | 8 | 5.595 | 0.699 | |||
Total | 9 | 132.4 | ||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
Intercept | 2.2336 | 0.478 | 4.670 | 0.002 | 1.131 | 3.337 |
Number of Endorsements | 1.9875 | 0.148 | 13.465 | 0.000 | 1.647 | 2.328 |
Therefore, the regression equation is:
If a professional athlete did 6 endorsements, what could they expect to profit according to the regression equation?
Answer: